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valentina_108 [34]
3 years ago
15

PLEASE HELP ME!!!!

Mathematics
1 answer:
Anettt [7]3 years ago
5 0
1. 8r + 4 = 10 + 2r
-4 -4
8r = 6 + 2r
-2r -2r
6r = 6
R= 1

2. -2(x + 3) = 4x - 3
-2x - 6 = 4x - 3
+3 +3
-2x -3 = 4x
+2x +2x
-3 = 6x
————-
6 6
-1/2 = x
3. 5 + 3(q - 4) = 2(q + 1)
5 + 3q - 12 = 2q + 2
-7 + 3q = 2q + 2
+7 +7
3q = 2q + 9
-2q -2q
Q = 9
4. 7x - 4 = -2x + 1 + 9x - 5
7x - 4 = 7x - 4
-7x -7x
-4 = -4
+4 +4
0 = 0
Infinite answers
5. 8x + 6 - 9x = 2 - x -15
-x +6 = - 13 - x
+ x +x
6 = -13
No solution
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e. (q-3)(q-4)

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4

Step-by-step explanation:

5 times 4 is 20, which leaves 4

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A 42 gram sample of a substance that's used to treat thyroid disorders has a k-value of 0.124. Find the substance's half-life, i
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Half life of sample = 5.59 days

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Here decay constant k = 0.124

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          t_\frac{1}{2}=\frac{ln2}{0.124}=5.59\boldsymbol{\texttt{ days}}

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An IQ test is designed so that the mean is 100 and the standard deviation is 18 for the population of normal adults. Find the sa
melisa1 [442]

Answer:

At least 98 people need to be sampled. It is not a huge number, that is, it is not difficult to sample 98 people, so it is a reasonable sample size for a real world calculation.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

In this question:

We need a sample size of at least n.

n is found when M = 3. We have that \sigma = 18.

M = z*\frac{\sigma}{\sqrt{n}}

3 = 1.645*\frac{18}{\sqrt{n}}

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Simplifying by 3

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Rounding up,

At least 98 people need to be sampled. It is not a huge number, that is, it is not difficult to sample 98 people, so it is a reasonable sample size for a real world calculation.

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