All categories

3 years ago

A camera regularly priced at 295 was placed on sale at 236. What percent of the regular price was the sale price?

Mathematics

1 answer:

skad [1K]3 years ago

6 0

Answer:

80%

Step-by-step explanation:

regular price was given as $295.

The sale of the camera was $236.

Needed Percentage of the regular price =( 236/295)

= 0.8

=(0.8 × 100%)

= 80%

You might be interested in

A print shop orders 58 T-shirts. They order 16 pink T-shirts, and six times as many blue T-shirts as white T-shirts. How many bl

Pepsi [2]

The have ordered 36 blue T-shirts.
___________________

How I got it --- So, we take away 16 from 58. You get 42.
________________________________________

So, from then, you know 36 is 6 times as many as 6, right? ( Because 6 x 6 = 36)
___________________________________________________________

So, then, you have ordered 36 blue shirts and 6 white shirts, because 36 + 6 =42.
______________________________________________________

Glad I could help, and good luck!
_________________________
_________________________
_________________________

3 0

3 years ago

Read 2 more answers

In the diagram m angle ACB = 61 Find m angle BCD

Marina86 [1]

we are given that

angle(ACF)=90

angle(ACB)=61

sum of all angles along any line is 180

so, we get

angle(ACF)+angle(ACD)=180

we can plug value

90+angle(ACD)=180

angle(ACD)=90

now, we can use formula

angle(ACD)=angle(ACB)+angle(BCD)

now, we can plug values

and we get

90=61+angle(BCD)

90-61=61-61+angle(BCD)

angle(BCD)=29................Answer

7 0

3 years ago

Read 2 more answers

Average precipitation for the first 7 months of the year, the average precipitation in toledo, ohio, is 19.32 inches. if the ave

Colt1911 [192]

Part A:

The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\sigma}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

$P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{2.44}\right) \\ \\ =1-P(z\ \textless \ -0.5410) \\ \\ =1-0.29426=\bold{0.7057}$

Part B:

The probability that an n randomly selected samples of a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

$P(x\ \textgreater \ a)=1-P(x\ \textless \ a)=1-P\left(z\ \textless \ \frac{a-\mu}{\frac{\sigma}{\sqrt{n}}}\right)$

Given that the average precipitation in Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that 5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:

 $P(x\ \textgreater \ 18)=1-P(x\ \textless \ 18) \\ \\ =1-P\left(z\ \textless \ \frac{18-19.32}{\frac{2.44}{\sqrt{5}}}\right) \\ \\ =1-P(z\ \textless \ -1.210) \\ \\ =1-0.1132=\bold{0.8868}$

7 0

3 years ago

Last year, Tim rode his bike a total of 50 3/8 miles. This year, he rode his bike a total of 258 3/4 miles. Which of the followi

oksano4ka [1.4K]

Answer:

Step-by-step explanation:

7 0

3 years ago

Find the slope of the line that passes through the given points. (10,-15) (13,-17)

Studentka2010 [4]

M=-2/3

This is because it’s the slope I got and I don’t know how to explane it

4 0

3 years ago