A camera regularly priced at 295 was placed on sale at 236. What percent of the regular price was the sale price?

Mathematics

1 answer:

skad [1K]3 years ago

6 0

Answer:

80%

Step-by-step explanation:

regular price was given as $295.

The sale of the camera was $236.

Needed Percentage of the regular price =( 236/295)

= 0.8

=(0.8 × 100%)

= 80%

You might be interested in

What is the decimal equivalent of 8%

Agata [3.3K]

I believe it would be 0.08

4 0

3 years ago

2, 6, 18, 54. 162,...

grigory [225]

9514 1404 393

Answer:

$\text{c. }f(n)=3f(n-1);f(1)=2$

Step-by-step explanation:

The first term is 2, so part of the recursive definition is ...

f(1) = 2

The common ratio is 6/2 = 3, so each term is 3 times the previous one. That part of the recursive definition is ...

f(n) = 3·f(n -1)

These two parts of the definition match choice C.

3 0

3 years ago

jerry has 60 coins consisting of quarters and dimes. The coins combined value is $9.45. Find out how are quarters and how many a

jekas [21]

Eq. 1 .10x + .25y = 9.45
Eq. 2 x + y = 60 rewrite as x = 60 - y and substitute into equation 1.

.10(60 - y) + .25y = 9.45
6 - .1y + .25y = 9.45
6 + .15y = 9.45
.15y = 3.45
y = 23
60 - 23 = 37

23 quarters
37 dimes

23* .25 = 5.75
37 * .1 = 3.70
5.75 + 3.70 =9.45

7 0

3 years ago

2,4,6,8...<br> What is the 32nd term of this sequence?

Elza [17]

Answer:

omg im dum i said all the numbers up to 64 i could have just multiplied its 64 xD

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

Plzzzzzzzzzzzzzz i really need someone to help me!!!<br> ASAP!!

Pavlova-9 [17]