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Furkat [3]
3 years ago
7

The sum of 3 numbers is 131. the second of three numbers is seven more than twice the first. the third number is 12 less than th

e first
Mathematics
1 answer:
arsen [322]3 years ago
6 0
A+b+c = 131

b = 7 + 2a and c = a - 12
 so a + 7+2a + a-12 = 131
then 4a -5 = 131
then 4a = 136
and a = 34....so b= 75 and c = 22....check 34+75+22=131√
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lesantik [10]

Answer:

(a).

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(b).

from general equation:

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common difference:

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8 0
3 years ago
X = y 2 - 1
pochemuha
Your answer would be option B. 2y² - y - 6 = 0. This is because if you were to substitute x = y² - 1 into the equation 2x - y = 4, you would get 2(y² - 1) - y = 4, which expands into 2y² - 2 - y = 4, and then simplifies to 2y² - y - 6 = 0.
I hope this helps!
7 0
3 years ago
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V125BC [204]

Answer:

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Step-by-step explanation:

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8 0
3 years ago
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klio [65]
The answer is 6 1/4, because if you making 1/2 = 2/4, 2 + 3 = 5, the 4 stays the same, so its 5 5/4, and to make it proper, you make it 6 1/4
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8 0
2 years ago
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