Question

please help How much heat does it take to raise the temperature of 9.0 kg of wood from 12C to 97C? The specific heat of wood is 1.68 kJ/(kgC). Use Q = mc(Tf - Ti). A. 760 kJ B. 1300 kJ C. 180 kJ D. 1500 kJ

Answer 1

Answer:

$Q = 1300 kJ$

Explanation:

As we know that heat require to change the temperature of the object is given as

$Q = mC \Delta T$

here we know that

m = mass = 9 kg

C = 1.68 kJ/kg

$\Delta T = 97 - 12$

$\Delta T = 85 degree C$

now from above formula we will have

$Q = 9\times 1.68 \times 10^3 \times 85$

$Q = 1300 kJ$

Answer 2

Q=mc(Tf-Ti)
   = (9Kg)(1.68 KJ/KgC)(97-12)
   = 1285.2 KJ
   ~ 1300 KJ