All categories

4 years ago

When the compasses are moved close to a wire with a current which will the compasses point

Physics

2 answers:

romanna [79]4 years ago

6 0

It can alter the direction of the compass

Sindrei [870]4 years ago

4 0

<span>In this demonstration, there is a single compass and a piece of wire that is perpendicular to the plane that the compass sits on. The wire with current flowing through it can alter the direction the compass needle points.</span>

You might be interested in

PLEASE HELP!!!!

Wewaii [24]

Answer: Local governments can resolve a conflict by cooperating and spreading the costs of expensive projects. What kinds of problems cause state governments to help local governments? No economic growth or improvements are problems that cause governments to help local governments.

6 0

3 years ago

What contributions did J.J. Thomson make to atomic history?

luda_lava [24]

J.J. Thomson discovered electrons and noticed that an atom can be divided. Also, he concluded atoms are made of positive cores and negatively charged particles within it.

4 0

3 years ago

A soft tennis ball is dropped onto a hard floor from a height of 1.50 m and rebounds to a height of 1.10 m. (a) Calculate its ve

Gemiola [76]

Answer:

(a) v = 5.42m/s

(b) vo = 4.64m/s

(d) Δy = 5.11*10^-3m

Explanation:

(a) The velocity of the ball before it hits the floor is given by:

$v=\sqrt{2gh}$ (1)

g: gravitational acceleration = 9.8m/s^2

h: height where the ball falls down = 1.50m

$v=\sqrt{2(9.8m/s^2)(1.50m)}=5.42\frac{m}{s}$

The speed of the ball is 5.42m/s

(b) To calculate the velocity of the ball, after it leaves the floor, you use the information of the maximum height reached by the ball after it leaves the floor.

You use the following formula:

$h_{max}=\frac{v_o^2}{2g}$ (2)

vo: velocity of the ball where it starts its motion upward

You solve for vo and replace the values of the parameters:

$v_o=\sqrt{2gh_{max}}=\sqrt{2(9.8m/s^2)(1.10m)}=4.64\frac{m}{s}$

The velocity of the ball is 4.64m/s

(c) The acceleration is given by:

$a=\frac{\Delta v}{\Delta t}=\frac{v_o-v}{3.50*10^{-3}s}=\frac{4.64m/s-(-5.42m)/s}{3.50*10^{-3}s}=2874.285\frac{m}{s^2}$

$a=\frac{\Delta v}{\Delta t}=\frac{v_o-v}{3.50*10^{-3}s}=\frac{4.64m/s-5.42m/s}{3.50*10^{-3}s}=-222.85\frac{m}{s^2}$

The acceleration of the ball is 2874.28/s^2

(d) The compression of the ball is:

$\Deta y=\frac{v^2}{2(a)}=\frac{(5.42m/s)^2}{2(2874.28m/s^2)}=5.11*10^{-3}m$

THe compression of the ball when it strikes the floor is 5.11*10^-3m

4 0

3 years ago

What is the mass of a 735-N weight on Earth?

Allisa [31]

W = mg, Assuming g ≈ 9.8 m/s² on the earth surface.

735 N = m* 9.8

735/9.8 = m

75 = m

Mass , m = 75 kg. B.

3 0

3 years ago

Based on the graph, describe how momentum changes with time for an object in free fall. If you can help, I would be so grateful.

pochemuha

With time, momentum increases as it builds speed assuming their is nothing in the way to stop it. Based on the graph, you can see that example being displayed as the line on the graph gets higher

4 0

3 years ago