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3 years ago

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A 1200 kg car traveling east at 4.5 m/s crashes into the side of a 2100 kg truck that is not moving. During the collision, the v

ehicles get stuck together. What is their velocity after the collision? A. 2.9 m/s east B 1.6 m/s east C. 2.6 m/s east D. 1.8 m/s east

1 answer:

zhenek [66]3 years ago

4 0

Answer:

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Explanation:

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When you use paper money to pay for food, the money is a _____.

Tpy6a [65]

Answer: The correct answer for the fill in the blank is - medium of exchange.

Explanation-

When we use paper money to pay for food, the money is a medium of exchange as we are exchanging our money with their food. So, it plays a role of medium of exchange in purchasing our food.

On the other hand, unit of account is also a feature of money but it only indicates the price of food at which we are purchasing it. Store of value is used when we store our money as a wealth, then it becomes store of value .

Hence, medium of exchange is the correct answer.

8 0

3 years ago

The distance from earth to mars ranges between 780,000,000 km and 380,000,000 km depending on the time of the year. The speed of

ivann1987 [24]

Answer:

The minimum time, t = 21.11 m

Explanation:

Given,

The maximum distance between the Earth and Mars, d = 780,000,000 km

The maximum distance between the Earth and Mars, d = 780,000,000 km

The speed of the light, c = 300,000 km/s

The distance and speed of the object is related using the formula,

v = d / t

t = d / v

The minimum time it takes for data transmission is when the distance between the Mars and the Earth is at minimum.

Therefore,

t = 380,000,000 km / 300,000 km/s

= 1266.67 s

= 21.11 minutes

Hence, the minimum time it takes for data transmitted by the Mars Surveyor to reach earth, t = 21.11 minutes

6 0

3 years ago

At a given instant in time, two cars are traveling at different velocities, one twice as large as the other. Based on this infor

Sati [7]

Answer: No, is not possible.

Explanation:

We have two cars traveling at different velocities, one with velocity v and other with velocity 2*v

We want to know of it is possible to say which of these two cars has the larger acceleration at this instant of time.

Acceleration is the rate of change of the velocity, for example, if acceleration = 0, the velocity does not change.

Notice that knowing only the velocity at a given instant of time, we do not have any way of knowing the acceleration of each car.

Such that acceleration is given by the second Newton's equation:

F = m*a

force equals mass times acceleration.

We do not know any of these quantities for the cars, so we can not say anything about the accelerations.

We also could know the average acceleration if we know the change in velocity over an interval of time, such that:

Av acceleration = (change in velocity)/(interval of time)

But here we do not have a change in velocity, so again, we can't say anything about the acceleration.

3 0

3 years ago

La estrella mas proxima a la tierra esta a 2 años de luz. Calcula esta distancia en unidades del SI

tino4ka555 [31]

Answer:

$2\ ly=1.89\times 10^{16}\ m$

Explanation:

The question says that, "The closest star to the earth is 2 light years away. Calculate this distance in SI units".

Given that,

The distance between the closest star and the Earth is 2 light years.

The SI unit of distance is m. It means we need to convert light years to meters. We know that,

$1\ ly=9.461\times 10^{15}\ m$

2 light-years means,

$2\ ly=2\times 9.461\times 10^{15}\ m\\\\=1.89\times 10^{16}\ m$

So, the required distance is equal to $1.89\times 10^{16}\ m$ .

5 0

3 years ago

A LASIK vision-correction system uses a laser that emits 10-ns-long pulses of light, each with 3.0 mJ of energy. The laser beam

lyudmila [28]

<span>P = energy/t = 0.0025/1E-8 = 250000 W
I(ave) = P/A = 250000/(pi*0.425E-3^2) = 4.4056732E11 W/m^2
I(peak) = 2I(ave) = 8.8113463E11 W/m^2
Electric field E = sqrt(I(peak)*Z0) = 1.8219499E7 V/m, where
free-space impedance Z0 = sqrt(µ0/e0) = 376.73031 ohms</span>

7 0

3 years ago