1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marin [14]
3 years ago
7

D^2y/dx^2+4dy/dx-12y=cos2x

Mathematics
1 answer:
rjkz [21]3 years ago
3 0
If you're solving for x, you'd move all the terms containing x to the left side of the equation:

d^2y/dx^2+4y/x-12y-cos^2(x)+sin^2(x)=0

If you're solving for y, you'd simplify both sides of the equation, then isolating the variable:

y=xcos(2x)
You might be interested in
What is the quotient of 2 1/4 and 5/8
Charra [1.4K]
If you would like to find the quotient of 2 1/4 and 5/8, you can calculate this using the following steps:

2 1/4 = 9/4

2 1/4 / 5/8 = 9/4 / 5/8 = 9/4 * 8/5 = 18/5 = 3 3/5

The correct result would be 3 3/5.
8 0
3 years ago
Given that 18f = 33g, identify the ratio off to g in simplest form.
Kobotan [32]

Answer:

11/6

Step-by-step explanation:

18f = 33g

f/g = 33/18 = 11/6

8 0
2 years ago
Read 2 more answers
I need help answering these questions, methods appreciated on how to do each one.
xxMikexx [17]

Answer:

get rickrolled

Step-by-step explanation:

4 0
3 years ago
The _____ were victims of attempted genocide ?
Marta_Voda [28]
B Jews and Armenians
7 0
3 years ago
The following data lists the ages of a random selection of actresses when they won an award in the category of Best​ Actress, al
Valentin [98]

Answer:

a) p_v =P(t_{(9)}

The p value is higher than the significance level given 0.01, so then we can conclude that we FAIL to reject the null hypothesis. And we can say that the true difference for Best Actresses is not significantly lower than the mean for Best​ Actors at 1% of significance.

b) The 99% confidence interval would be given by (-21.469;2.069)

c) We got the same conclusion as part a, sicne the confidence interval contains the value 0, we FAIL to reject the null hypothesis that the difference between the two

Step-by-step explanation:

Part a

Let put some notation  

x=actor's age , y = actress's age

x: 58 41 36 36 34 33 48 37 37 43

y: 26 27 34 26 35 29 23 42 30 34

The system of hypothesis for this case are:

Null hypothesis: \mu_y- \mu_x \geq 0

Alternative hypothesis: \mu_y -\mu_x

The first step is calculate the difference d_i=y_i-x_i and we obtain this:

d: -32, -14, -2, -10, 1, -4, -25, 5, -7, -9

The second step is calculate the mean difference  

\bar d= \frac{\sum_{i=1}^n d_i}{n}= -9.7

The third step would be calculate the standard deviation for the differences, and we got:

s_d =\frac{\sum_{i=1}^n (d_i -\bar d)^2}{n-1} =11.451

The 4 step is calculate the statistic given by :

t=\frac{\bar d -0}{\frac{s_d}{\sqrt{n}}}=\frac{-9.7 -0}{\frac{11.451}{\sqrt{10}}}=-2.679

The next step is calculate the degrees of freedom given by:

df=n-1=10-1=9

Now we can calculate the p value, since we have a left tailed test the p value is given by:

p_v =P(t_{(9)}

The p value is higher than the significance level given 0.01, so then we can conclude that we FAIL to reject the null hypothesis. And we can say that the true difference for Best Actresses is not significantly lower than the mean for Best​ Actors at 1% of significance.

Part b

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The confidence interval for the mean is given by the following formula:  

\bar d \pm t_{\alpha/2}\frac{s}{\sqrt{n}} (1)  

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,9)".And we see that t_{\alpha/2}=3.25  

Now we have everything in order to replace into formula (1):  

-9.7-3.25\frac{11.451}{\sqrt{10}}=-21.469  

-9.7+3.25\frac{11.451}{\sqrt{10}}=2.069  

So on this case the 99% confidence interval would be given by (-21.469;2.069)

Part c

We got the same conclusion as part a, sicne the confidence interval contains the value 0, we FAIL to reject the null hypothesis that the difference between the two means is 0.

8 0
3 years ago
Other questions:
  • which of the following best describes the bases of a cylinder? A. Congruent B. Polygons C. Parallel D. Discs (Check All That App
    12·1 answer
  • 6.) Haven has 29 stickers to share with her 8 friends. How many stickers will each friend get if each friend gets the same amoun
    10·1 answer
  • Help me, please ASAP 20 POINTS!!!!!!!
    11·2 answers
  • Please answer this in two minutes
    8·1 answer
  • Write an ordered pair for each point graphed below.
    10·2 answers
  • What is the product of 8/15 times 6/5 and 1/3
    7·2 answers
  • Complete this statement: 8 ounces is to one cup as __________ ounces is to 10 cups.
    6·2 answers
  • Ericka observed the total variation in the water level over 6.2 years to be −13.64 mm. She compared this to the average annual t
    11·2 answers
  • please help it’s due soon marking brainlest look at my examples determine whether the two expressions are equivalent. if so tell
    8·1 answer
  • Simplify 25(14–27)+25÷16. a 28/5 b16/5 c 31/5 d 36/5
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!