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marin [14]
4 years ago
7

D^2y/dx^2+4dy/dx-12y=cos2x

Mathematics
1 answer:
rjkz [21]4 years ago
3 0
If you're solving for x, you'd move all the terms containing x to the left side of the equation:

d^2y/dx^2+4y/x-12y-cos^2(x)+sin^2(x)=0

If you're solving for y, you'd simplify both sides of the equation, then isolating the variable:

y=xcos(2x)
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Which object has the same y-intercept as a function y=2/3x-3?
Licemer1 [7]

The 4th option.

The values with no x or y attached are the y intercept

6x - 7y = 21

Subtract 6x from both sides

6x - 7y - 6x = 21 - 6x

-7y = 21 - 6x

Divide both sides by - 7

-7y/-7 = 21/-7 - 6x/-7

Y = -3 +6x/7


The why intercept, -3 is the same as the one in the question


7 0
4 years ago
Mina created a miniature rocket launcher, and the graph shows the height of one of her
Kazeer [188]

Answer:

Work individually or in teams of two to construct and launch paper rockets using a teacher-built PVC-pipe launcher.

Following the flight of their rocket, calculate the altitude their rocket achieved.

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5 0
3 years ago
Wharton how many times have you taken the gmat
zhannawk [14.2K]
Who is Wharton. I don’t get it is it a convo
7 0
3 years ago
A regular triangular pyramid has a base and lateral faces that are congruent equilateral triangles. It has a lateral surface are
TEA [102]
We know that

[lateral surface area of a regular triangular pyramid]=3*[area of one <span>equilateral triangle]
so
[area of one </span>equilateral triangle]=lateral surface/3-----> 81/3-----> 27 ft²

[<span>surface area of the regular triangular pyramid]=lateral area+area of the base

area of the base is equals to the area of the lateral sides because are </span>equilateral triangles

therefore
area of the base=27 ft²

[surface area of the regular triangular pyramid]=81+27----> 108 ft²

the answer is
<span>the surface area of the regular triangular pyramid is 108 ft</span>²
4 0
3 years ago
Please help!!!! I am going to fail!!! I will mark you brainiest!
schepotkina [342]

Answer:

ok what do you need help with

7 0
3 years ago
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