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marin [14]
3 years ago
7

D^2y/dx^2+4dy/dx-12y=cos2x

Mathematics
1 answer:
rjkz [21]3 years ago
3 0
If you're solving for x, you'd move all the terms containing x to the left side of the equation:

d^2y/dx^2+4y/x-12y-cos^2(x)+sin^2(x)=0

If you're solving for y, you'd simplify both sides of the equation, then isolating the variable:

y=xcos(2x)
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Answer:

So we got:

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More attention for (n^{\frac{-1}{3}}\right))^6\\

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