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marin [14]
4 years ago
7

D^2y/dx^2+4dy/dx-12y=cos2x

Mathematics
1 answer:
rjkz [21]4 years ago
3 0
If you're solving for x, you'd move all the terms containing x to the left side of the equation:

d^2y/dx^2+4y/x-12y-cos^2(x)+sin^2(x)=0

If you're solving for y, you'd simplify both sides of the equation, then isolating the variable:

y=xcos(2x)
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3 years ago
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Given f(x) = 4x + 2, find f-1(3).
Alexxandr [17]

Answer:

  1/4

Step-by-step explanation:

The inverse function tells you the input value that corresponds to the given output value of the function.

<h3>Application</h3>

You want f^-1(3), which is the value of x such that f(x) = 3.

  f(x) = 3 = 4x +2

  1 = 4x . . . . . . subtract 2

  1/4 = x . . . . . divide by 4

The inverse function of 3 is 1/4:

  \boxed{f^{-1}(3)=\dfrac{1}{4}}

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2 years ago
Find the value of given expression<br><br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B62500%7D%20" id="TexFormula1" title=" \
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Step-by-step explanation:

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kotegsom [21]
This is a linear differential equation of first order. Solve this by integrating the coefficient of the y term and then raising e to the integrated coefficient to find the integrating factor, i.e. the integrating factor for this problem is e^(6x). 
<span>Multiplying both sides of the equation by the integrating factor: </span>

<span>(y')e^(6x) + 6ye^(6x) = e^(12x) </span>

<span>The left side is the derivative of ye^(6x), hence </span>

<span>d/dx[ye^(6x)] = e^(12x) </span>

<span>Integrating </span>

<span>ye^(6x) = (1/12)e^(12x) + c where c is a constant </span>

<span>y = (1/12)e^(6x) + ce^(-6x) </span>

<span>Use the initial condition y(0)=-8 to find c: </span>

<span>-8 = (1/12) + c </span>
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<span>Hence </span>

<span>y = (1/12)e^(6x) - (97/12)e^(-6x)</span>
7 0
3 years ago
Please answer quick, will give brainliest!!
jonny [76]

Answer:

can u write the question

Step-by-step explanation:

pls the I will answer it

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