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2 years ago

15

Consider the characteristics of the center, shape, spread, and any unusual features. Which statement correctly describes the dat

a?

1 answer:

saul85 [17]2 years ago

6 0

Answer: b

Step-by-step explanation:

You might be interested in

Pwease help me anyone. thanks :-) :-) :-) :-) :-) :-) :-) :-)!!!!

adell [148]

A)
$x+3$

b)
$x(x+3)=340\\
x^2+3x-340=0$

c)
$x(x+3)=340\\ x^2+3x-340=0\\
\Delta=3^2-4\cdot1\cdot(-340)=9+1360=1369\\\sqrt{\Delta}=37\\
x_1=\dfrac{-3-37}{2}=-20\\
x_2=\dfrac{-3+37}{2}=17$

It's 17.

3 0

2 years ago

You have 12 1/3 yards and you need 47 yards how many more yards of fabric do you need

Lady bird [3.3K]

Answer:

34 2/3

Step-by-step explanation:

You need 47 yards. You have 12 1/3

47 - 12 1/3. So we'll break it down.

47 - 12 = 35.

Now, 35 + 12 1/3 would make 47 1/3

So now 35 - 1/3=34 2/3

34 2/3 + 12 1/3 = 47

4 0

2 years ago

6/13=3/c. Solve for C

nignag [31]

X=13/2 or 6.5 i hope this helps

7 0

2 years ago

May's bakeshop makes triple brownies that cost $1.50 each. Past experience shows 20% of the brownies will spoil. Assuming may wa

Simora [160]

You must add 20 and 40, and divide it.

4 0

3 years ago

Suppose a random sample of n = 16 observations is selected from a population that is normally distributed with mean equal to 101

stepan [7]

Answer:

101, 3, 0.025, 0.7416

Step-by-step explanation:

Given that a random sample of n = 16 observations is selected from a population that is normally distributed with mean equal to 101 and standard deviation equal to 12.

As per central limit theorem we have

a) Mean of sample mean = $E(\bar x) =\\ \mu =101$

Std deviation of sample mean = $\frac{\sigma}{\sqrt{n} } =3$

Mean = 101

Std dev =3.00

b) $P(\bar x >107) = P(Z>\frac{107-101}{3} )\\= P(Z>2) = 0.025$

c) the probability that the sample mean deviates from the population mean μ = 101 by no more than 4.

= $P(|\bar x-101|) \leq 4\\= P(|z|\leq 1.13)\\= 2(0.3708)\\=0.7416$

6 0

3 years ago