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olga_2 [115]
3 years ago
12

What is the vertex form of this equation y=3(x-2)^2-(x-5)^2​

Mathematics
1 answer:
jek_recluse [69]3 years ago
6 0

Answer: Hello, it would be 3(x-2)^2-(x-5)^2

Step-by-step explanation:

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Question is attached could you please help me and explain how you got your answer?
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Okay so combine like terms
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Now to check:
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3 years ago
In what quadrant does the angle 9pi/ 5 terminate?
aev [14]

the angle 4pi/5 in quadrent 2

3 0
3 years ago
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If line segment BH = 3, line segment BF = 10, line segment GH= 2, find HD 15 11 10.5 ?
pav-90 [236]

HD = 10.5

Step-by-step explanation:

Given BH = 3, GH = 2, BF = 10

Step 1: To find HF:

HF = BF – BH

HF = 10 – 3

HF = 7

Step 2: To find HD:

We know that if two chords intersects inside a circle, the product of the lengths of the segments of one chord equals the product of the lengths of the segments of the other chord.

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Hence, the value of HD = 10.5.

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Answer:

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Step-by-step explanation:

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