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Yuki888 [10]
3 years ago
9

What are the values of r and a1 for 1/4(2)k-1

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

c

Step-by-step explanation:

Rasek [7]3 years ago
3 0

Given:

\sum_{k=1}^{6}\dfrac{1}{4}(2)^{k-1}

To find:

The values of r and a_1.

Solution:

We have,

\sum_{k=1}^{6}\dfrac{1}{4}(2)^{k-1}

Here,

a_k=\dfrac{1}{4}(2)^{k-1}        ...(i)

We know that, kth term of a GP is

a_k=a_1(r)^{k-1}        ...(ii)

From (i) and (ii), we get

a_1=\dfrac{1}{4} and r=2

Therefore, the correct option is C.

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The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)

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