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Yuki888 [10]
3 years ago
9

What are the values of r and a1 for 1/4(2)k-1

Mathematics
2 answers:
Kipish [7]3 years ago
7 0

Answer:

c

Step-by-step explanation:

Rasek [7]3 years ago
3 0

Given:

\sum_{k=1}^{6}\dfrac{1}{4}(2)^{k-1}

To find:

The values of r and a_1.

Solution:

We have,

\sum_{k=1}^{6}\dfrac{1}{4}(2)^{k-1}

Here,

a_k=\dfrac{1}{4}(2)^{k-1}        ...(i)

We know that, kth term of a GP is

a_k=a_1(r)^{k-1}        ...(ii)

From (i) and (ii), we get

a_1=\dfrac{1}{4} and r=2

Therefore, the correct option is C.

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<em>Comment on factoring</em>

Factoring ax^2 +bx +c = 0 requires you find factors of ac that have a sum of b. Here, you're looking for factors of 2·7 = 14 that have a sum of 9. If you're observant, you realize that 2+7=9, so 2 and 7 are the factors you want.

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