Domain of: 3x-2
Solution: -Inf < x < Inf
Interval Notation: (-Inf, Inf)
Inf = Infinity (Replace "Inf" with the infinity symbol)
"-" = Negative sign
We use the Work formula to solve for the unknown in the problem which is W = F x d. First, we solve for the Net Force acting on the car. The Net Force is the summation of all forces acting on the object. For this case, we assume that Friction Force is negligible thus the Net Force is equal to:
F = mgsinα in terms of SI units and in terms of english units we have F = m(g/g₀)(sin α) where g₀ is the proportionality factor, 32.174 ft lb-m / lb-f s²
F = 2500 (32.174/32.174) (sin 12°) = 519.78 lb
W = Fd = 519.78 lb (400 ft) = 207912 ft - lb or 20800 ft-lb
$48.75
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0.21951 Reapeating cause the decimal does not terminate
<h3>Solution :-</h3>
➩ 70 = 12 + 9x - 2 ( x + 6 )
➩ 70 = 12 + 9x - 2x - 12
➩ 70 = 0 + 7x
➩ 70 = 7x
Here we can use 2 methods
Methods :-
- Trial and error method :- By adding,subtracting , multiplying or dividing the same variable or constant on LHS & RHS
- Transposing :- by transposing a term from LHS to RHS or RHS to LHS
• Trial and error
By dividing with 7 on both sides
➩ 70/7 = 7x/7
➩ x = 10
• Transposing
By transposing 7 from RHS. to LHS
➩ 70/7 = x
➩ x = 10
Hence , x = 10
