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Vladimir [108]
3 years ago
5

What is 2.343 rounded to the nearest tenth

Mathematics
2 answers:
elena-s [515]3 years ago
3 0
I'm pretty sure it's 2.3
Rufina [12.5K]3 years ago
3 0
To round to the tenths place, you look at the hundredths place. In this case, the hundredths place is a 4. Since 4 is lower than 5, u round down. So the answer is 2.300
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The entrepreneurship club is ordering potted plants for
mamaluj [8]

Answer:I have this and I’m in 7th grade lol

Step-by-step explanation:

7 0
3 years ago
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what are two fractions that make 17/20. please don't respond if you don't know the answer because I'm wasting points please and
BartSMP [9]
1. 34/40
2. 51/60
Hope this helps!!!!
6 0
3 years ago
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Divide Rational Expressions<br> In the following exercises, divide.
guapka [62]

Answer:

\displaystyle \mathbf{\frac{5}{(c+4)}}

Step-by-step explanation:

<u>Division of Rational Expressions</u>

When dividing two rational expressions like f(c) / g(c), it's usually easier to multiply the numerator by the reciprocal of the denominator: f(c) * (1/g(c)). The reciprocal is just flipping the numerator and the denominator.

Let's find the following division:

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}

First, we factor the polynomials where possible.

c^2-64 = (c-8)(c+8)

3c^2+26c+16=(3c+2)(c+8)

c^2-4c-32=(c-8)(c+4)

15c+10=5(3c+2)

Substituting:

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}=\frac{\frac{(c-8)(c+8)}{(3c+2)(c+8)}} {\frac{(c-8)(c+4)}{5(3c+2)}}

Multiplying by the reciprocal of the denominator:

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}=\frac{(c-8)(c+8)}{(3c+2)(c+8)}\cdot  \frac{5(3c+2)}{(c-8)(c+4)}

Simplifying by (c+8)(3c+2)(c-8):

\displaystyle \frac{\frac{c^2-64}{3c^2+26c+16}} {\frac{c^2-4c-32}{15c+10}}=\frac{5}{(c+4)}

Answer:

\displaystyle \mathbf{\mathbf{\frac{5}{(c+4)}}}

5 0
3 years ago
At Hogwarts School of Witchcraft and Wizardry, the Sorting Hat chooses one of four houses for each first-year student. If 4 stud
weeeeeb [17]

Answer:

Probability that they are the youngest is 0.000549

Step-by-step explanation:

Given

Number of students = 16

Selected students = 4

Let n = number of students

n = 16

Let r = selections

r = 4

We're interested in selecting 4 students out of 16; the keyword, selection means we're dealing with combination because order is not important.

So,

Solving for nCr

nCr = n!/((n-r)!r!)

16C4 = 16!/((16-4)!4!)

16C4 = 16!/(12!4!)

16C4 = 16 * 15 * 14 * 13 * 12!/(12!4!)

16C4 = 16 * 15 * 14 * 13 / 4 * 3 * 2 * 1

16C4 = 1820 ways

There are 1820 ways of selecting 4 students from a total of 1820.

Only one of these ways can the four of them be the youngest.

So, probability = 1/1820

Probability = 0.0005494506

Probability that they are the youngest is 0.000549 (approximately)

3 0
3 years ago
HELPPP!
Anika [276]

Answer:

  c.  x ≈ 1.71, y ≈ 6.29, z ≈ 60.71

Step-by-step explanation:

You are at a bit of a disadvantage with this problem, because both the hint and the answer choices are incorrect.

The matrix equation is ...

AX=B\\\\\left[\begin{array}{ccc}-1&1&0\\4&3&0\\1&-7&1\end{array}\right]\left[\begin{array}{c}x&y&z\end{array}\right]=\left[\begin{array}{c}8&12&15\end{array}\right]

Contrary to what the hint is telling you, the multiplication by the inverse must be on the left:

A^{-1}AX=A^{-1}B\\\\X=A^{-1}B

Using appropriate tools to compute the inverse, this becomes ...

\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{ccc}-3&1&0\\4&1&0\\31&6&7\end{array}\right]\left[\begin{array}{c}8&12&15\end{array}\right]\\\\\left[\begin{array}{c}x&y&z\end{array}\right]=\dfrac{1}{7}\left[\begin{array}{c}-12&44&425\end{array}\right]\approx\left[\begin{array}{c}-1.714&6.286&60.714\end{array}\right]

The closest match is choice C.

6 0
4 years ago
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