2 years ago

Ņ Wy+4) - y = 6 is a quadratic equation. O True False

Mathematics

1 answer:

otez555 [7]2 years ago

5 0

Answer:

Answer: The answer would be B. False.

(Please give me a thanks it'll help out a

lot.)

Step-by-step explanation:

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I need the answer to this

spin [16.1K]

Answer:

parallel as if we place the ond the coordinate grkd they will form lines paral.el to each other(;

7 0

2 years ago

Solve the system of linear equations by ellmination. 5x + 9y = -11 3x + 9y = -3 A. (-4,-1) -B. (-1, –4) C. (-4,1) D. (1,-4)

valentina_108 [34]

Answer:

Step-by-step explanation:

5x + 9y = -11

3x + 9y = -3

5x + 9y = -11

-3x - 9y = 3

2x = -8

x = -4

-12 + 9y = -3

9y = 9

y = 1

(-4, 1)

Answer is C

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2 years ago

Determine whether the statement is true or false. If it is true, explain why.

Over [174]

True.

Since $y^4 \geq 0$ , $y' = -1 - y^4 \ \textless \ 0$ and the solutions are decreasing functions.

8 0

2 years ago

Given: JK tangent, KH=16, HE=12 Find: JK.

Y_Kistochka [10]

Answer: $JK=8$

Step-by-step explanation:

You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:

$JK^2=KE*KH$

You know that:

$KH=KE+HE$

Then KE is:

$KE=KH-HE$

$KE=16-12$

$KE=4$

Now you can substitute the value of KE and the value of KH into $JK^2=KE*KH$ and solve for JK. Then the result is:

$JK^2=4*16\\JK^2=64\\JK=\sqrt{64}\\JK=8$

7 0

2 years ago

Kate wants to spend less than $100 per day to rent a car. A car rents for $45 per day plus $0.25 per mile. Write, solve, and gra

Bezzdna [24]

Money to be spent per day <$100
To rent a car:
Minimum amount per day= $45
Amount per mile= $0.25

Hence amount spent depends on distance travelled.
If distance travelled= x; fee for travel= 0.25x

Hence finally we need the fare to be less than $100
And fare is $45+0.25x

So the final inequality is 0.25x+45<100.

Hope it helps.

8 0

2 years ago