Answer:
<u>The solutions to this quadratic equation are 10 and 3.</u>
Step-by-step explanation:
1. Let's recall the formula for solving this type of equations, called quadratic equations:
x = ( - b +/- √ b² - 4ac)/ 2a
The equation given is x2 – 13x + 30 = 0,
where a = 1, b = - 13 and c = 30
Now replacing with the real values, we have
x = [ - (-13) +/- √ (-13)² - 4 * 1 * 30] / 2 * 1
x = [ 13 +/- √ 169 - 120] / 2
x = [13 +/- √ 49]/ 2
x = [ 13 +/- 7 ]/ 2
<u>x₁ = 13 + 7/2 = 20/2 = 10</u>
<u>x₂ = 13 - 7/2 = 6/2 = 3</u>
Answer:
a is an even number and b is an odd number
Step-by-step explanation:
if a is even and b is even then the sum would be even ex.10+6=16. I'd a and b are both odd the sum would be even ex. 13+9=22. one has to be odd and one has to be even for the sum to be odd ex. 5+4=9
Answer:
x equals 4.6
Step-by-step explanation:
if u need explanation plz tell me so i can help
Answer:
b. 65
a. The notation f(-2) means that we want to evaluate the value of the equation when x = -2
Step-by-step explanation:
A. The notation f(-2) means that we want to evaluate the value of the equation when x = -2
B. We will simply substitute the value of 2 for x
f(x) = 6(8-x) + 5
f(-2) = 6(8 - (-2)) + 5
f(-2) = 6(8 + 2) + 5
f(-2) = 6(10) + 5 = 60 + 5 = 65
