Circle: x^2+y^2=121=11^2 => circle with radius 11 and centred on origin.
g(x)=-2x+12 (from given table, find slope and y-intercept)
We can see from the graphics that g(x) will be almost tangent to the circle at (0,11), and that both intersection points will be at x>=11.
To show that this is the case,
substitute g(x) into the circle
x^2+(-2x+12)^2=121
x^2+4x^2-2*2*12x+144-121=0
5x^2-48x+23=0
Solve using the quadratic formula,
x=(48 ± √ (48^2-4*5*23) )/10
=0.5058 or 9.0942
So both solutions are real and both have positive x-values.
Answer:
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Step-by-step explanation:
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Answer:
Step-by-step explanation:
This equation is written in slope-intercept form, meaning that the value next to the variable (7.50) is the rate (slope) and the other number is the y-intercept (9).
So you can say that you mowed the lawn at $9 up front and 7.50 every hour (or half-hour whatever you want).
Answer: Click on the cell where you want the result of the calculation to appear. Type = (press the equals key to start writing your formula) Click on the first cell to be added (B2 in this example) Type + (that's the plus sign)
Step-by-step explanation:
