Answer:
1222
Step-by-step explanation:
You have a triangular prism on top of a rectangular prism. The surface area is the sum of the areas of the exposed faces.
Starting with the triangular prism, the surface area is the area of the two triangular bases plus the area of the two rectangular sides (the bottom rectangular face is ignored).
A = ½ (10) (12) + ½ (10) (12) + (13) (9) + (13) (9)
A = 60 + 60 + 117 + 117
A = 354
The surface area of the rectangular prism is the area of the two rectangular bases (front and back), plus the two walls (left and right), plus the bottom, plus the top (minus the intersection with the top prism).
A = (19) (11) + (19) (11) + (9) (11) + (9) (11) + (19) (9) + (19) (9) − (10) (9)
A = 209 + 209 + 99 + 99 + 171 + 171 − 90
A = 868
So the total surface area is:
354 + 868
1222
In the event that a line has no y-intercept, that implies it never converges the y-intercept, so it must be parallel to the y-intercept. This implies it is a vertical line, for example, . This slant of this line is vague. In the event that the line has no x-intercept, at that point it never meets the x-intercept, so it must be parallel to the x-pivot.
If x-intercept is -2 the line would be vertical as the y-intercept = 0.
Answer:
Not factorable.
Step-by-step explanation:
We have a trinomial (3 terms). We factor by splitting the middle term 4t into factors of -7 (the last term) which add to 4.
-7 = 1 * -7
4t= 1t+-7t doesn't work
4t=-1t+7t doesn't work
This is not factorable.
Answer:
We cannot say that the mean wake time are different before and after the treatment, with 98% certainty. So the zopiclone doesn't appear to be effective.
Step-by-step explanation:
The goal of this analysis is to determine if the mean wake time before the treatment is statistically significant. The question informed us the mean wake time before and after the treatment, the number of subjects and the standard deviation of the sample after treatment. So using the formula, we can calculate the confidence interval as following:
![IC[\mu ; 98\%] = \overline{y} \pm t_{0.99,n-1}\sqrt{\frac{Var(y)}{n}}](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%20%5Coverline%7By%7D%20%5Cpm%20t_%7B0.99%2Cn-1%7D%5Csqrt%7B%5Cfrac%7BVar%28y%29%7D%7Bn%7D%7D)
Knowing that 
:
![IC[\mu ; 98\%] = 98.9 \pm 2.602\frac{42.3}{4} \Rightarrow 98.9 \pm 27.516](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%2098.9%20%5Cpm%202.602%5Cfrac%7B42.3%7D%7B4%7D%20%5CRightarrow%2098.9%20%5Cpm%2027.516)
![IC[\mu ; 98\%] = [71.387 ; 126,416]](https://tex.z-dn.net/?f=IC%5B%5Cmu%20%3B%2098%5C%25%5D%20%3D%20%5B71.387%20%3B%20126%2C416%5D)
Note that ![102.8 \in [71.384 ; 126.416]](https://tex.z-dn.net/?f=102.8%20%5Cin%20%5B71.384%20%3B%20126.416%5D)
so we cannot say, with 98% confidence, that the mean wake time before treatment is different than the mean wake time after treatment. So the zopiclone doesn't appear to be effective.
Well 3 3/8 as a decimal is 3.375 and 1 5/6 as a decimal is 1.8333333333 and if you add those its <span>5.208333333</span>.
