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MakcuM [25]
2 years ago
13

If 5 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline 5, what is the value of x? â€"3

â€"2 2 3.
Mathematics
1 answer:
Tatiana [17]2 years ago
8 0

The value of x is 3.

Given that,

If  5 + 20 \times 2^{2-3x},

And Baseline = 10 \times 2^{-2x}+5

We have to find,

The value of x?

According to the question,

To determine the value of x in the equation following all the steps given below.

Equation; \rm 5 + 20 \times 2^{2-3x} = 10 \times 2^{-2x}+5

  • Step1; Subtract 5 from both sides,

                   \rm5-  5 + 20 \times 2^{2-3x} = 10 \times 2^{-2x}+5-5\\\\\rm 20 \times 2^{2-3x} = 10 \times 2^{-2x}

  • Step2; Divided by 10 on both sides,

                    \rm 20 \times 2^{2-3x} = 10 \times 2^{-2x}\\\\\dfrac{ 20 \times 2^{2-3x} }{10}= \dfrac{10 \times 2^{-2x}}{10}\\\\\rm 2 \times 2^{2-3x} = 2^{-2x}

  • Step3; Rewrite the term into their power form and add the powers,

                   \rm 2 \times 2^{2-3x} = 2^{-2x}\\\\2^1 \times 2^{2-3x} = 2^{-2x}\\\\2^{2-3x+1} = 2^{-2x}\\\\

  • Step4; The base is the same on both sides, we equate exponents,        

                    \rm 2-3x+1 = -2x\\\\-3x+2x = -1-2\\\\-x = -3\\\\x=3

Hence, The required value of x is 3.

For more details about the Exponent refer to the link given below.

brainly.com/question/25959524

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3 years ago
Salina, Tamara, and Uma are working on their homework together. Salina tells her friends that she got θ=52∘θ=52∘ for the inverse
svlad2 [7]

Answer:

The values reported by Uma, Salina, and Tamara are all possible values for inverse cosine

Step-by-step explanation:

Solution:-

- The solution to the inverse "cosine" problem would have a general form:

                                    θ = cos^-1 ( a )

Where,  a: Any arbitrary constant, - 1 < a < 1

- The value of θ = 52° was reported by Salina suggests that the answer lies in the first quadrant of a cartesian plane where ( sin (θ) , cos (θ) , tan (θ) ) have positive values for "a".

Hence,                            0 < a < 1 , θ = 52°

- The value of θ = 128° was reported by Tamara suggests that the answer lies in the second quadrant of a cartesian plane where ( sin (θ) ) have positive values for "a" and (cos (θ) , tan (θ) have negative values for "a". So for cos (128):

Hence,                           -1 < a < 0 , θ = 128°

- The value of θ = 308° was reported by Uma suggests that the answer lies in the fourth quadrant of a cartesian plane where ( cos (θ) ) have positive values for "a" and (sin (θ) , tan (θ) have negative values for "a". So for cos (308):

Hence,                           0 < a < 1 , θ = 308°

- The angle θ reported by Uma and Salina are similar solution because of property law of complementary angles:

                                     cos (θ) = cos ( 360 - θ )

Where, θ = 52°,            cos (52°) = cos( 308°)  .. Uma and Salina conform

However,                      cos ( 180 - θ ) = - cos (θ)  

                                     cos(128) = - cos ( 52 ) .... Uma and Tamara conform.

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3 years ago
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