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Marizza181 [45]
3 years ago
12

‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️PLEASE HELP!!! PLEASE EXPLAIN AND ONLY ANSWER IF YOU KNOW YOU HAVE THE CORRECT ANSWE

R!!!
Evaluate the following expression using the values given:


x^3 - 2y^2 - 3x^3 + z^4


X=3 y=5 z = -3
Mathematics
2 answers:
ahrayia [7]3 years ago
6 0
So firstly you just have to plug in the values as given into a calculator.
(3)^3 - 2(5^2) - 3(3)^3 + (-3)^4 .
It is also very important that when you plug in your values they must be inside parenthesis, followed by calculating the powers first, then the multiplication, then lastly the subtraction.
luda_lava [24]3 years ago
5 0

Hello.

1. -23

x3−2y2−3x3+z4 Arranging similar monomials

=x3−3x3−2y2+z4

=−2x3−2y2+z4

=−2(3)3−2(5)2+(−3)4

=−2×27−2×25+81

=−54−50+81

=−104+81

=−23

Have a nice day

You might be interested in
Is 3,4,5 a Pythagorean triple
son4ous [18]

Answer:

Yes  because  it fits the Pythagorean Theorem

Step-by-step explanation:

see:   5 ^2 = 25

and   3^2 + 4^2 =  9 + 16 = 25

25 = 25

so it is

8 0
3 years ago
I need help with this problem. Given: BC = 10 inches AC = √50 inches m∠CBD = 60° m∠CAD = 90° Calculate the exact area of the sha
Nikitich [7]

Answer:

Area of the shaded region = 23.33 in²

Step-by-step explanation:

Area of a sector = \frac{\theta}{360}(\pi r^{2})

Where θ = Central angle subtended by an arc

r = radius of the circle

Area of the sector BCD = \frac{60}{360}(\pi) (10^{2})

                                       = 52.36 in²

Area of equilateral triangle BCD = \frac{\sqrt{3} }{4}(\text{Side})^2

                                                      = \frac{\sqrt{3} }{4}(10)^2

                                                      = 25\sqrt{3} in²

                                                      = 43.30 in²

Area of the shaded portion in ΔBCD = 52.36 - 43.3

                                                             = 9.06 in²

Area of sector CAD = \frac{90}{360}(\pi)(\sqrt{50})^2

                                 = 39.27 in²

Area of right triangle CAD = \frac{1}{2}(\text{Base})(\text{Height})

                                            = \frac{1}{2}(\text{AC})(\text{AD})

                                            = \frac{1}{2}(\sqrt{50})(\sqrt{50})

                                            = 25 in²

Area of the shaded part in the ΔACD = 39.27 - 25

                                                                         = 14.27 in²

Area of the shaded part of the figure = 9.06 + 14.27

                                                                = 23.33 in²

8 0
3 years ago
How do I do this problem I am stuck .
vekshin1
4p - 9 = -193
4p = -193 = 9 
4p = -184
p = -184/4
p = -46
3 0
4 years ago
Read 2 more answers
(4x+5) (3x+1) -3 (x+1)<br>​
ollegr [7]

Answer:

-36x^3 - 69x^2 - 34x - 5

Step-by-step explanation:

(4x + 5) (3x + 1) -3 (x + 1)

(4x + 5) (3x + 1) ( -3x - 1)

12x^2 + 4x + 15x +5

Combine like terms

12x^2 + 19x + 5 (-3x - 1)

-36x^3 -57x^2 - 15x^2 -5

Combine like terms

-36x^3 - 69x^2 - 34x - 5

4 0
2 years ago
K(a)= 4a-4, Find k(-9)
FromTheMoon [43]

We simply replace a with -9

k(-9) = 4 * -9 - 4

k(-9) = -40

:)

5 0
3 years ago
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