Answer:
3 7/12 kg
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
Step-by-step explanation:
On sunday , sheldon bought 4 1/2 kg of plant food. He uses 1 2/3 kg on his strawberry plants and used 1/4 kg for his tomato plants. b. Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time. He will use the same amounts of plant food as before. How much plant food will be need? Does he have enough left to do so.
Total plant bought = 4 1/2 kg
Strawberry = 1 2/3 kg
Tomato = 1/4 kg
Strawberry + tomato
= 1 2/3 + 1/4
= 5/3 + 1/4
= 20+3/12
= 23/12 kg
Total remaining after Sunday
= Total - used
= 4 1/2 - 23/12
= 9/2 - 23/12
= 54-23/12
= 31/12
= 2 7/12 kg
Sheldon wants to feed his strawberry plants 2 more times and his tomato plants one more time.
Strawberry = 2 × 1 2/3
= 2 × 5/3
= 10/3 kg
Tomato = 1 × 1/4
= 1/4 kg
Total plant needed to feed strawberry two more times and tomato 1 more time
= 10/3 kg + 1/4 kg
= 40+3/12
= 43/12 kg
= 3 7/12 kg
He will need 3 7/12 kg of plant
He doesn't have enough plant to feed strawberry 2 more times and tomato 1 more time
Answer:
The length of the rectangle is 9 cm
Step-by-step explanation:
Given: The length of rectangle(l) = (x+3) cm and a width of rectangle (w) = 
cm a
Also, perimeter of rectangle is 24 cm.
Perimeter of rectangle is to add the lengths of all the four sides.
Perimeter of rectangle (P) is given by;
P=2(l+w)
Substituting the value of P = 24 cm , l = (x+3) cm and w =
then,
Divide by 2 both sides of an equation;
Combine like terms;
Subtract 3 from both the sides we get;
Simplify:
Multiply both sides by 
we get
Therefore, length of rectangle(l) = (x+3) = 6+3 = 9 cm
Answer:
18
Step-by-step explanation:
2 x 3^2
2 x 9
18
A) zeroes
P(n) = -250 n^2 + 2500n - 5250
Extract common factor:
P(n)= -250 (n^2 - 10n + 21)
Factor (find two numbers that sum -10 and its product is 21)
P(n) = -250(n - 3)(n - 7)
Zeroes ==> n - 3 = 0 or n -7 = 0
Then n = 3 and n = 7 are the zeros.
They rerpesent that if the promoter sells tickets at 3 or 7 dollars the profit is zero.
B) Maximum profit
Completion of squares
n^2 - 10n + 21 = n^2 - 10n + 25 - 4 = (n^2 - 10n+ 25) - 4 = (n - 5)^2 - 4
P(n) = - 250[(n-5)^2 -4] = -250(n-5)^2 + 1000
Maximum ==> - 250 (n - 5)^2 = 0 ==> n = 5 and P(5) = 1000
Maximum profit =1000 at n = 5
C) Axis of symmetry
Vertex = (h,k) when the equation is in the form A(n-h)^2 + k
Comparing A(n-h)^2 + k with - 250(n - 5)^2 + 1000
Vertex = (5, 1000) and the symmetry axis is n = 5.
