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pychu [463]
3 years ago
11

Alex wants to construct a line segment through R that makes the same angle with line segment QR as line segment PQ. The figure b

elow shows a step to construct a congruent angle at R:

Mathematics
2 answers:
scZoUnD [109]3 years ago
7 0

Answer : To construct a line segment through R which would have the same angle with line segment QR . With the co-relation of segment QR which is same to segment PQ which means that angle Q and angle R are corresponding angles.

So, to construct the same angle with the segment keep the pointed compass end on R by measuring the same distance at the angle Q. Just draw the curve at R and there you are.

Natali5045456 [20]3 years ago
4 0
I found the corresponding images of this question. Please see attachment. I have also identified my answer on the attachment. 


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Find the volume of the triangular pyramid to the nearest whole number (number only in your answer) Please help....
sertanlavr [38]

Answer:

Volume of pyramid = 317 units³

Step-by-step explanation:

Volume do triangular pyramid = ⅓ × Base Area × height of pyramid

Base area = ½*bh = ½*8*14 = 56 units²

Height of pyramid = 17

Volume of pyramid = ⅓ × 56 × 17

Volume of pyramid = 317 units³ (to nearest whole number)

7 0
2 years ago
Read 2 more answers
The data sets show the years of the coins in two collections. Derek's collection: 1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910
KATRIN_1 [288]

Answer:

Derek's collection :

Mean= 1929

Median= 1930

Range= 54

IQR = 48

MAD= 23.75

Paul's collection:

Mean= 1929

Median= 1929.5

Range= 15

IQR = 6

MAD= 3.5

Step-by-step explanation:

1950, 1952, 1908, 1902, 1955, 1954, 1901, 1910

Mean is given by:

(1950+1952+ 1908+1902+1955+1954+1901+1910)/8

=1929

absolute deviation from mean is:

|1950-1929|= 21

|1952-1929|= 23

|1908-1929|= 21

|1902-1929|= 27

|1955-1929|= 26

|1954-1929|= 25

|1901-1929|= 28

|1910-1929|= 19

from the mean of absolute deviation gives the MAD of the data i.e.

(21+23+21+27+26+25+28+`9)/8

23.75

 

:arrange the given data to get the range and median

   1901   1902    1908   1910    1950  1952    1954   1955

The minimum value is: 1901

Maximum value is: 1955

Range is: Maximum value-minimum value

         Range=1955-1901

Range= 54

median is (1910+1950)/2

1930

   the lower set of data=

  1901   1902    1908   1910

first quartile becomes

1902+1908)/2

Q1=1905

and upper set of data is:

1950  1952    1954   1955

we find the median of the  upper quartile or third quartile is:

1952+1954)/2=1953

Q3-Q1=1953-1905=

IQR=48

 

Paul's collection:

1929, 1935, 1928, 1930, 1925, 1932, 1933, 1920

Mean is given by:

1929+1935+ 1928+ 1930+ 1925+ 1932+1933+1920)/8

1929

absolute deviation from mean is:

|1929-1929|=0

|1935-1929|= 6

|1928-1929|= 1

|1930-1929|= 1

|1925-1929|= 4

|1932-1929|= 3

|1933-1929|= 4

|1920-1929|= 9

Hence, we get:

MAD=0+6+1+1+4+3+4+9/8

28/8

3.5

arrange the data in ascending order we get:

1920   1925   1928   1929   1930   1932   1933   1935  

Minimum value= 1920

Maximum value= 1935

Range=  15 (  1935-1920=15 )

The median is between 1929 and 1930

Hence, Median= 1929.5

Also, lower set of data is:

1920   1925   1928   1929  

the first quartile or upper quartile is

1925+1928/2

1926.5

and the upper set of data is:

1930   1932   1933   1935  

We have

1932+1933)/2

1932.5

IQR is calculated as:

Q3-Q1

6

7 0
3 years ago
Jasmine's cell phone company charges her $35 an month for phone service plus 0.50 for each text message.How many text messages d
VashaNatasha [74]

Jasmine sent 17 texts. 0.50×34=17

17=35=52

6 0
2 years ago
CAN SOMEONE PLEASE HELP ME OUT PLEASE I WOULD APPRECIATE IT VERY MUCH
tatyana61 [14]

Answer:Decreasing

Step-by-step explanation:

Focus only on the 8-10 interval for x. Note that for x=8 , y=1, for x=9, y=0 and for x=10, y=-1. Y is obviously decreasing for 8 .

6 0
3 years ago
Please help me the last question is wrong
egoroff_w [7]

Answer:

                         

Step-by-step explanation:

5 0
2 years ago
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