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3 years ago

How do I do this problem I am stuck .

Mathematics

2 answers:

GarryVolchara [31]3 years ago

6 0

4p-9= -193
+9 +9
4p = -184
/4 /4
p = -46

vekshin13 years ago

3 0

4p - 9 = -193
4p = -193 = 9
4p = -184
p = -184/4
p = -46

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Use to model the problem draw the block to show your work

natulia [17]

First of all be more spusific in your question

3 0

3 years ago

Help! How would I solve this trig identity?

NeTakaya

Using simpler trigonometric identities, the given identity was proven below.

<h3>How to solve the trigonometric identity?</h3>

Remember that:

$sec(x) = \frac{1}{cos(x)} \\\\tan(x) = \frac{sin(x)}{cos(x)}$

Then the identity can be rewritten as:

$sec^4(x) - sen^2(x) = tan^4(x) + tan^2(x)\\\\\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\$

Now we can multiply both sides by cos⁴(x) to get:

$\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)} = \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)} \\\\\\\\cos^4(x)*(\frac{1}{cos^4(x)} - \frac{1}{cos^2(x)}) = cos^4(x)*( \frac{sin^4(x)}{cos^4(x)} + \frac{sin^2(x)}{cos^2(x)})\\\\1 - cos^2(x) = sin^4(x) + cos^2(x)*sin^2(x)\\\\1 - cos^2(x) = sin^2(x)*sin^2(x) + cos^2(x)*sin^2(x)$

Now we can use the identity:

sin²(x) + cos²(x) = 1

$1 - cos^2(x) = sin^2(x)*(sin^2(x) + cos^2(x)) = sin^2(x)\\\\1 = sin^2(x) + cos^2(x) = 1$

Thus, the identity was proven.

If you want to learn more about trigonometric identities:

brainly.com/question/7331447

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7 0

1 year ago

A man has 10 more dimes than quarters. he has $2.75 how many of each coin does he have?

Anton [14]

5 quarters, 15 dimes

q + 10 = d
0.25q + 0.1d = 2.75

0.25q + 0.1(q + 10) = 2.75
0.25q + 0.1q + 1 = 2.75
0.35q = 1.75
q = 5

Check:

0.25(5)+ 0.1(15)= 2.75
1.25 + 1.5 = 2.75
2.75 = 2.75 :)

4 0

2 years ago

!!!!!HELP!!!!! 25 POINTS!!!

cluponka [151]

Answer:

Formula: A = 48,000(1+0.02)^t

salary after 30 years: $ 86,945.35

Step-by-step explanation:

Hi, to answer this question we have to apply an exponential growth function:

A = P (1 + r) t

Where:

p = initial salary

r = raising rate (decimal form)

t= years

A = salary after t years

Replacing with the values given:

A = 48,000 (1+ 2/100)^t

A = 48,000(1+0.02)^t

Salary after 30 years: substitute t=30

A = 48,000(1+0.02)^30

A = 48,000(1.02)^30

A=$ 86,945.35

Feel free to ask for more if needed or if you did not understand something.

6 0

3 years ago

Read 2 more answers

A University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students. A s

Alla [95]

Answer:

The point estimate for this problem is 0.48.

Step-by-step explanation:

We are given that a University wanted to find out the percentage of students who felt comfortable reporting cheating by their fellow students.

A survey of 2,800 students was conducted and the students were asked if they felt comfortable reporting cheating by their fellow students. The results were 1,344 answered "Yes" and 1,456 answered "no".

Let $\hat p$ = proportion of students who felt comfortable reporting cheating by their fellow students

Now, point estimate ( $\hat p$ ) is calculated as;

$\hat p=\frac{X}{n}$

where, X = number of students who answered yes = 1,344

n = number of students surveyed = 2,800

So, Point estimate ( $\hat p$ ) = $\frac{1,344}{2,800}$

= 0.48 or 48%

5 0

3 years ago