F = qE + qV × B
where force F, electric field E, velocity V, and magnetic field B are vectors and the × operator is the vector cross product. If the electron remains undeflected, then F = 0 and E = -V × B
which means that |V| = |E| / |B| and the vectors must have the proper geometrical relationship. I therefore get
|V| = 8.8e3 / 3.7e-3
= 2.4e6 m/sec
Acceleration a = V²/r, where r is the radius of curvature.
a = F/m, where m is the mass of an electron,
so qVB/m = V²/r.
Solving for r yields
r = mV/qB
= 9.11e-31 kg * 2.37e6 m/sec / (1.60e-19 coul * 3.7e-3 T)
= 3.65e-3 m
Answer:
a) i₈ = 0.5 i₄, b) i₁₀ = 0.3 i₃, i₁₀ = 0.8 i₈
Explanation:
For this exercise we use ohm's law
V = i R
i = V / R
we assume that the applied voltage is the same in all cases
let's find the current for each resistance
R = 4 Ω
i₄ = V / 4
R = 8 Ω
i₈ = V / 8
we look for the relationship between these two currents
i₈ /i₄ = 4/8 = ½
i₈ = 0.5 i₄
R = 3 Ω
i₃ = V3
R = 10 Ω
i₁₀ = V / 10
we look for relationships
i₁₀ / 1₃ = 3/10
i₁₀ = 0.3 i₃
i₁₀ / 1₈ = 8/10
i₁₀ = 0.8 i₈
The correct answer is
D. Groups and Families
I did the quiz nd this was the right answer
Hopes this helps :)
The velocity of an electron that has been accelerated through a difference of potential of 100 volts will be 5.93 *
m/s
Electrons move because they get pushed by some external force. There are several energy sources that can force electrons to move. Voltage is the amount of push or pressure that is being applied to the electrons.
By conservation of energy, the kinetic energy has to equal the change in potential energy, so KE=q*V. The energy of the electron in electron-volts is numerically the same as the voltage between the plates.
given
charge of electron = 1.6 ×
C
mass of electron = 9.1 ×
kg
Force in an electric field = q*E
potential energy is stored in the form of work done
potential energy = work done = Force * displacement
= q * (E * d)
= q * (V) = 1.6 ×
* 100
stored potential energy = kinetic energy in electric field
kinetic energy = 1/2 * m * 
= 1/2 * 9.1 ×
* 
equation both the equations
1/2 * 9.1 ×
*
= 1.6 ×
= 0.352 *
m/s
= 35.2 * 
= 5.93 *
m/s
To learn more about kinetic energy in electric field here
brainly.com/question/8666051
#SPJ4
Answer:
The mass of the aluminum chunk is 258 g
Explanation:
Given;
mass of steel container = 120-g
mass of water = 150 g
initial temperature of water, = 25°C
mass of copper cube,
= 200 g
initial temperature of the copper cube,
= 85°C
initial temperature of the aluminum chunk
= 5.0°C
Neglecting heat loss, heat exchanged by the two metallic objects is the same since initial temperature is equal to final temperature of water.

where;
is specific heat capacity of aluminum
is change in temperature of aluminum
is the specific heat capacity of copper
is the change in temperature of copper

Therefore, the mass of the aluminum chunk is 258 g