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jek_recluse [69]
3 years ago
5

Use at least two to three completed content related sentences to explain why physics is considered the basic science. Provide at

least one example to explain how physics relates to other sciences
Physics
2 answers:
Virty [35]3 years ago
6 0
Idk your answer sorry
Lyrx [107]3 years ago
4 0
It is considered the basic science because other sciences depend on it to develop .For example , studying the space and the motion of planets need physics and we can't go sometimes to the space and do our experiment , also it uses in X-ray which consists of electromagnetic waves .
physics is needed in more sciences like chemisrty , geology ect..
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Please answer this. Science 7th grade.
saw5 [17]
B should be the answer
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3 years ago
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How is a physical change different from a chemical change
lorasvet [3.4K]
There's a few differences. In a physical change the actual substance doesn't change, where in a chemical change with chemical reaction, a new substance is formed. Physical change can be reversed, and chemical change can't.
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3 years ago
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An ice skater applies a horizontal force to a 150 N block on frictionless, level ice, causing the block to accelerate uniformly
Molodets [167]

Answer:

<em>The friction force has a magnitude of 54 N and points to the left</em>

Explanation:

<u>Friction Force</u>

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

Fr=\mu N

Where \mu is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W

Thus, the friction force is:

Fr=\mu W

The ice skater accelerates a block to the right on frictionless horizontal ice and then stops pushing it. The block continues to move at a constant speed when it finds a sand-covered surface with a kinetic coefficient of friction of 0.36.

The friction force is:

Fr=0.36*150

Fr = 54 N

The friction force has a magnitude of 54 N and points to the left

5 0
3 years ago
It has been suggested that rail guns based on this principle could accelerate payloads into earth orbit or beyond. Find the dist
-BARSIC- [3]

Answer:

The distance of the bar D = 1153 km

Explanation:

The electric force is the one that takes place between electric charges.

The electric force with which two point charges are attracted or repelled at rest is directly proportional to their product, inversely proportional to the square of the distance that separates them and acts in the direction of the line that joins them.

Recall that:

Electrical force(F) = I*B*L

where;

I = the current,

B = the magnetic field strength,

L = the length of the bar

However;

From the second equation of motion,

F = Ma

Since; (F) = I*B*L

Then,

Ma = IBL,

where;

M is the mass;

a is the acceleration

Making the acceleration (a) the subject of the formula, we have

a = IBL/M

Similarly;

From the third equation of motion;

v^2= u^2+2as,

where v and u are the final velocity and the initial velocity respectively

Here u = 0

Also; let distance s = D

Then

v^2 = 2aD

where;

a = IBL/M

Making the distance D  the subject of the formula, we get:

D = v^2/2a = v2*M/(2IBL)

D = 11200² × 20/(2×2300×0.86×0.55)

D = 1153047.155 m

D = 1153 km

8 0
3 years ago
A 4.0-kg ball with a velocity of in the collides head-on elastically with a stationary 2.0-kg ball. What are the velocities of t
Rus_ich [418]

Complete question:

4.0 kg ball with a velocity of 4 m/s in the +x-direction collides head-on elastically with a stationary 2.0-kg ball. What are the velocities of the balls after the collision.

Answer:

The final velocity of the first is 1.33 m/s

The final velocity of the second ball is 5.33 m/s

Explanation:

Given;

mass of the first ball, m₁ = 4.0 kg

mass of the second ball, m₂ = 2.0 kg

initial velocity of the first ball, u₁ = 4 m/s

initial velocity of the second ball, u₂ = 0

let the final velocity of the first ball after collision = v₁

also, let the final velocity of the second ball after collision = v₂

Apply the principle of conservation of linear momentum;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

4(4) + 0 = 4v₁ + 2v₂

16 = 4v₁ + 2v₂

8 = 2v₁ + v₂ -------- equation (1)

Apply one-directional velocity;

u₁ + v₁ = u₂ + v₂

4 + v₁ = 0 + v₂

4 + v₁ = v₂ --------- equation (2)

Substitute in equation (2) into equation (1)

8 = 2v₁ + v₂

8 = 2v₁ + (4 + v₁)

8 = 2v₁ + 4 + v₁

8 - 4 = 2v₁ + v₁

4 = 3v₁

v₁ = 4 / 3

v₁ = 1.33 m/s

Then, v₂ = 4 + v₁

v₂ = 4 + 1.33

v₂ = 5.33 m/s

6 0
3 years ago
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