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jek_recluse [69]
3 years ago
5

Use at least two to three completed content related sentences to explain why physics is considered the basic science. Provide at

least one example to explain how physics relates to other sciences
Physics
2 answers:
Virty [35]3 years ago
6 0
Idk your answer sorry
Lyrx [107]3 years ago
4 0
It is considered the basic science because other sciences depend on it to develop .For example , studying the space and the motion of planets need physics and we can't go sometimes to the space and do our experiment , also it uses in X-ray which consists of electromagnetic waves .
physics is needed in more sciences like chemisrty , geology ect..
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jeyben [28]
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4 0
2 years ago
A solid ball of radius rb has a uniform charge density rho.
Oksana_A [137]

Note: question B is incomplete.

Complete Question

A solid ball of radius rb has a uniform charge density ρ.

a.  What is the magnitude of the electric field E(r) at a distance r>rb from the center of the ball?  Express your answer in terms of ρ, rb, r, and ϵ0.

b.   What is the magnitude of the electric field E(r) at a distance r<rb from the center of the ball?  Express your answer in terms of ρ, r, rb, and ϵ0.

c.   Let E(r) represent the electric field due to the charged ball throughout all of space. Which of the following statements about the electric field are true?

1. E(0) = 0.

2. E(rb) = 0

3. lim E(r) = 0.

4. The maximum electric field occurs when r = 0.

5. The maximum electric field occurs when r = rb.

6. The maximum electric field occurs as r to infinity.

Answer:

a) the magnitude of E(r)= ρr³/3 ε₀r²

b) the magnitude at distance r from the centre E(r)= ρr/3 ε ₀ ( if r<rb)

c) statements 1(E(0) = 0), 3(E(0) = 0) and 5(The maximum electric field occurs when r = rb.) are true

Explanation:

given

charge density = ρ ,  ε

Volume of sphere , V = (⁴/₃)πr³

a) charge density = charge/volume

ρ = q ÷ V

make charge the subject of the formula

∴q = ρ × V=  ρ× (⁴/₃)πr³

where r³ = rb³(at distance rb³)

recall

E= q/4πε₀r²

E=  ρ × (⁴/₃)πrb³/4πε₀r²

∴E(r)= ρrb³/3 ε ₀r²

(b)  The Gaussian surface is inside the ball, therefore, surface only encloses a portion of ball's charge .

The net charge enclosed by the Gaussian surface is different to the of net charge enclosed in (a)

Recall

E= q/4πε₀r²

V= (⁴/₃)πr³

E=  ρ × (⁴/₃)πr³/4πε₀r²

∴E(r)= ρr/3 ε₀

(c)  E(0)= 0

limr-----∝

E(r)= 0

The maximum electric field occurs when r=rb.

4 0
3 years ago
What explains the information needed to calculate speed and velocity?
Ede4ka [16]
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3 0
3 years ago
What is the wavelength (in air) of a 13.0 khz vlf radio wave?
bonufazy [111]
Since,
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-i
5 0
3 years ago
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Answer:

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Explanation:

As we know that

potential at points A, B,C and D as V_A, V_B, V_C, V_D  and it is clear from the question that

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And we know that flow is always from higher to lower potential (for positive charge due to positive potential energy).

So the charge will accelerate from B toward C.

Hence, the correct option is A.

6 0
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