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frozen [14]
3 years ago
15

If you perform 40 J of work lifting a 10-N box from the floor to a shelf, how high is the shelf?

Physics
1 answer:
Kaylis [27]3 years ago
4 0
Before anything, if you are lifting the Work value have to be negative, reason is because the formula to the work of the weight is:

w = p \times d \times cos \:  \theta
*Photo to help you to visualize. (P = Weight Force, F = Force)

If you are lifting, you are exercising a force that opposes the Weight Force, Force up (lifting) and Weight Force down (gravity pulling).
This forms a 180 angle and the cos 180 = -1.

Well let's do the question:

Work (W) = -40 J (Joule = Kg x m^2/s^2)
(negative, explanation given)

Weight Force (P) = 10 N (Newton = kg x m/s^2)

Distance (D) = ?

W = P x d x cos theta

-> -40 = 10 x d x -1
-> -40 = -10 x d
-> d = -40/-10 (J/N)
-> d = 4 meters

d =j  \div n \\ d = ((kg \times  {m}^{2} ) \div  {s}^{2}) \div ((kg \times m) \div  {s}^{2}) \\ d = m \: (meters)

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If an object has a positive charge, are the electrons from another object more likely to be attracted to it or to repel it?
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attracted

Explanation:

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An electron enters a region with a speed of 5×10^6m/s and is slowed down at the rate of 1.25×10^-4m/s². How far does the electro
Mashutka [201]

1) The distance travelled by the electron is 1\cdot 10^{17} m

2) The time taken is 4.0\cdot 10^{10}s

Explanation:

1)

The electron in this problem is moving by uniformly accelerated motion (constant acceleration), so we can use the following suvat equation

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance travelled

For the electron in this problem,

u=5\cdot 10^6 m/s is the initial velocity

v = 0 is the final velocity (it comes to a stop)

a=-1.25\cdot 10^{-4} m/s^2 is the acceleration

Solving for s, we find the distance travelled:

s=\frac{v^2-u^2}{2a}=\frac{0-(5\cdot 10^6)^2}{2(-1.25\cdot 10^{-4})}=1\cdot 10^{17} m

2)

The total time taken for the electron in its motion can also be found by using another suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time taken

Here we have

u=5\cdot 10^6 m/s

v = 0

a=-1.25\cdot 10^{-4} m/s^2

And solving for t, we find the time taken:

t=\frac{v-u}{a}=\frac{0-5\cdot 10^6}{-1.25\cdot 10^{-4}}=4.0\cdot 10^{10}s

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

7 0
3 years ago
The noble gas neon is used for filling neon signs. Like other noble elements, it has a full octet (complete outer energy level)
DanielleElmas [232]

Answer:

C. unlikely to combine with other elements.

Explanation:

In Chemistry, electrons can be defined as subatomic particles that are negatively charged and as such has a magnitude of -1.

Valence electrons can be defined as the number of electrons present in the outermost shell of an atom. Valence electrons are used to determine whether an atom or group of elements found in a periodic table can bond with others. Thus, this property is typically used to determine the chemical properties of elements.

Noble gases are chemical elements with eight valence electrons and as such have a full octet. Some examples are argon, neon, etc.

Hence, the full octet makes the gas (neon) unlikely to combine with other elements.

7 0
3 years ago
The water line from the street to my house is 1 inch diameter and made of PVC (i.e. smooth). The line is roughly 450 ft long. Th
jekas [21]

Answer:

The right solution is "126 Psi".

Explanation:

The given values are:

P₁ = 130 psig

i.e.,

   = 130\times 6.894

   = 896.22 \ Kpa

or,

   = 896.22\times 10^3 \ Pa

Z₂ = 10ft

    = 3.05 m

\delta = 1000 kg/m³

According to the question,

Z₁ = 0

V₁ = V₂

As we know,

⇒  \frac{P_1}{\delta_g} +\frac{V_1^2}{2g} +Z_1=\frac{P_2}{\delta_g} +\frac{V_2^2}{2g} +Z_2

On substituting the values, we get

⇒  \frac{P_1}{\delta_g} +0+0=\frac{P_2}{\delta_g} +0+Z_2

⇒  \frac{896.22\times 10^3}{1000\times 9.8} =\frac{P_2}{1000\times 9.8} +3.05

⇒  P_2=866330 \ P_a

i.e.,

⇒       =866330\times 0.000145

⇒       =126 \ Psi

8 0
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