The center of mass is given by:
∑mx/∑m
m is the mass of each object
x is the position of each object
We will assign x = 0m to the 18kg mass, therefore x = 6m for the 6kg mass.
∑mx/∑m = (18×0+6×6)/(18+6) = 1.5m
The center of mass is located 1.5m away from the 18kg mass.
The total moment of inertia of the system about the center of mass is given by:
I = ∑mr²
I is the moment of inertia
m is the mass of each object
r is the distance of each object from the center of mass
We know r = 1.5m for the 18kg mass and the rod is 6m long, therefore the 6kg mass must be r = 4.5m from the center of mass.
I = 18(1.5)² + 6(4.5)²
I = 162kg×m²
Answer:
75457.54816 N
Explanation:
= Initial force
= Weight of car = 11547.83 N
= Smaller radius = 5 cm
= Larger radius = 19.56 cm
From Pascal's law we have
The force is 754.57548 N
Answer:
720 J
Explanation:
The gravitational potential energy that Essam loses for every metre is given by:
where
m=72 kg is Essam's mass
is the gravitational field strength
is the difference in height
By substituting the numbers into the formula, we find
<u>Answer:</u>
Chipmunk's average acceleration during the 2.07 s time interval = 0.1256
<u>Explanation:</u>
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
In this case we need to find acceleration value, we have initial velocity = 1.47 m/s, final velocity = 1.73 m/s and time taken = 2.07 seconds.
Substituting
1.73 = 1.47 + a * 2.07
a = 0.1256
Chipmunk's average acceleration during the 2.07 s time interval = 0.1256