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Brilliant_brown [7]
3 years ago
11

Two men, Joel and Jerry, each pushes an object that are identical on a horizontal frictionless floor starting from rest. Joel an

d Jerry are using the same force F. Jerry stops after 10 min, while Joel is able to push for 5.0 min longer. Compare the work they do.
Physics
1 answer:
Nataliya [291]3 years ago
7 0

Answer:

The work done by Joel is greater than the work done by Jerry.

Explanation:

Let suppose that forces are parallel or antiparallel to the direction of motion. Given that Joel and Jerry exert constant forces on the object, the definition of work can be simplified as:

W = F\cdot \Delta s

Where:

W - Work, measured in joules.

F - Force exerted on the object, measured in newtons.

\Delta s - Travelled distance by the object, measured in meters.

During the first 10 minutes, the net work exerted on the object is zero. That is:

W_{net} = W_{Joel} - W_{Jerry}

W_{net} = F\cdot \Delta s - F\cdot \Delta s

W_{net} = (F-F)\cdot \Delta s

W_{net} = 0\cdot \Delta s

W_{net} = 0\,J

In exchange, the net work in the next 5 minutes is the work done by Joel on the object:

W_{net} = W_{Joel}

W_{net} = F\cdot \Delta s

Hence, the work done by Joel is greater than the work done by Jerry.

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Consider two less-than-desirable options.
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Answer:

The force would be the same in both cases - option C.

Explanation:

The change in momentum is known as an impulse. In the two cases under consideration, the change in momentum is the same, thus impulse for both cases is the same.

Impulse is the average force multiplied by time interval.

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The average force in both cases is the same since the collision time is the same.

Thus option C is the correct answer.

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If the speed of an object is tripled, its kinetic energy will be
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if the speed of the object triples the kinetic energy becomes nine times the initial kinetic energy. If the speed of an object changes by a factor k, the change in the kinetic energy is of a factor k^2.

Explanation:

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A car is behind a truck going 25m/s on the highway. the car's driver looks for an opportunity to pass, guessing that his car can
Misha Larkins [42]

Velocity of cars = 25 m/s

Distance the car has to cover for passing truck = 40m

Distance of passing spot from the car coming from opposite direction = 400- 40 =360 m

Time available for the car to pass truck of 20 m length = Distance of passing spot from the car coming from opposite direction/relative velocity between cars

Time = 360/50 = 7.2 seconds

Suppose the truck is moving at the same speed of car.

  Distance traveled by car compared to truck is given by the expression

                   S = ut + \frac{1}{2} at^2, where S is the distance traveled, u is the initial velocity a is the acceleration and t is the ime taken.

      In this case u = 0, t = 7.2 s, a = 1 m/s^2

So distance traveled by car in 7.2s compared to truck = 0*7.2+\frac{1}{2} *1*7.2^2

So,     S = 0+ 25.92 = 25.92 m

So car will travel only travel 25.92 m

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7 0
3 years ago
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