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miskamm [114]
3 years ago
9

I just need help on number 14. Thank you very much.

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0

I believe you only need to know one angle.

For example, if you know angle 1, you can calculate angle 3. Angle 2 = angle 3 and angle 4 = angle 1.

Also, Angle 5= angle 1 and so on...

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Claire jogs 6 miles per hour and Megan jogs 5 miles per hour. they start together at their campsite and jog to an outpost 18 mil
horrorfan [7]

Answer:

16.364 miles

Step-by-step explanation:

Speed of Claire = 6 miles per hour

Speed of Megan= 5 miles per hour

Distance from camp site to out post = 18 miles

Time for Claire to travel=18/6= 3 hours

Time for Megan to travel = 18/5 = 3.6 hours

The time they meet will be equal

Claire distance= 18 + x

Megan distance = 18-x

Claire time =( 18+x)/6

Megan Tim =( 18-x)/5

(18+x)/6 =(18-x)/5

5(18+x)= 6(18-x)

90 +5x = 108-6x

11x=18

X=18/11

X=1.636 Miles

So the distance from the Outpost to where they meet = 18-1.636

= 16.364 miles

6 0
3 years ago
I need help answering these two questions . This is missing sides and Angles of Right Triangles
iren [92.7K]
1) Tanθ= opposite/adjacent
θ=Tan-1(9/7)
θ=52.125 = 52 degrees

2) Cosθ= adjacent/hypothesis
θ=Cos-1(5/12)
θ=65.376 = 65 degrees
8 0
2 years ago
How many different possible outcomes are there if you flip seven coins?
BARSIC [14]

Answer:

Because the coin is tossed 7 times and you get 2 outcomes (head or tail) for each one.

4 0
2 years ago
Read 2 more answers
Help ASAP
kipiarov [429]

Answer:round to the nearest tenth

Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
A certain brand of automobile tire has a mean life span of 35,000 miles, with a standard deviation of 2250 miles. Assume the lif
yawa3891 [41]

Answer:

Step-by-step explanation:

From the information given:

mean life span of a brand of automobile = 35,000

standard deviation of a brand of automobile = 2250 miles.

the z-score that corresponds to each life span are as follows.

the standard z- score formula is:

z = \dfrac{x - \mu}{\sigma}

For x = 34000

z = \dfrac{34000 - 35000}{2250}

z = \dfrac{-1000}{2250}

z = −0.4444

For x = 37000

z = \dfrac{37000 - 35000}{2250}

z = \dfrac{2000}{2250}

z = 0.8889

For x = 3000

z = \dfrac{30000 - 35000}{2250}

z = \dfrac{-5000}{2250}

z = -2.222

From the above z- score that corresponds to their life span; it is glaring  that the tire with the life span 30,000 miles has an unusually short life span.

For x = 30,500

z = \dfrac{30500 - 35000}{2250}

z = \dfrac{-4500}{2250}

z = -2

P(z) = P(-2)

Using excel function (=NORMDIST -2)

P(z) = 0.022750132

P(z) = 2.28th percentile

For x =  37250

z = \dfrac{37250 - 35000}{2250}

z = \dfrac{2250}{2250}

z = 1

Using excel function (=NORMDIST 1)

P(z) = 0.841344746

P(z) = 84.14th percentile

For x = 35000

z = \dfrac{35000- 35000}{2250}

z = \dfrac{0}{2250}

z = 0

Using excel function (=NORMDIST 0)

P(z) = 0.5

P(z) = 50th percentile

6 0
3 years ago
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