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Darina [25.2K]
4 years ago
11

BRAINLIESTTT ASAP! PLEASE HELP ME :)

Mathematics
2 answers:
Afina-wow [57]4 years ago
6 0

Answer:

What do you need help with, I can't help you right now because there is no problem.

Step-by-step explanation:

Troyanec [42]4 years ago
5 0

Answer:

What do you need help with, I can't help you right now because there is no problem.

Step-by-step explanation:

You can take a screenshot and post it if you would like

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Which number is less than -3 or greater than 5?
Anna71 [15]

Answer:

4

Step-by-step explanation:

7 0
4 years ago
Find the simplified product sqrt 2x^3 sqrt 18x^5
KatRina [158]
The first step to solving this is to remember the radical rules. They state that the product of roots that have the same index are equal to the root of the product. Knowing this,, the expression changes to the following:
\sqrt{2 x^{3} X 18 x^{5}  }
Next you'll add the two exponents together and then calculate the product.
\sqrt{36 x^{8} }
Lastly,, calculate the square root to find your answer.
6x^{4}
This means that the correct answer to your question will be 6x^{4}.
Let me know if you have any further questions
:)
4 0
3 years ago
Read 2 more answers
In the equation y = 3/4x + 10, what is the slope?
krok68 [10]

Answer:

The slope is 3/4

Step-by-step explanation:

8 0
4 years ago
In a function, y varies inversely with x. The constant of variation is 4. Which table could represent the function?
Nimfa-mama [501]
The equation will be y=4/x. u can make the table of variables by inserting the values of x in the equation. for suppose here, if x=1 then y=4 , x=2 then y=2 and so on.
5 0
3 years ago
Read 2 more answers
the axis of symmetry for the graph of the function is f(x) = 1/4x2 bx 10 is x = 6. what is the value of b?
Lady bird [3.3K]

we have

f(x)=\frac{1}{4} x^{2} +bx+10

This is a vertical parabola open upward

The axis of symmetry is equal to the x-coordinate of the vertex

The vertex is the point (h,k)

the equation of the axis of symmetry is x=h

In this problem

x=6

so the x-coordinate of the vertex is h=6

<u>Convert the quadratic equation in vertex form</u>

Group terms that contain the same variable, and move the constant to the opposite side of the equation

f(x)-10=\frac{1}{4} x^{2} +bx

Factor the leading coefficient

f(x)-10=\frac{1}{4}(x^{2} +4bx)

Complete the square. Remember to balance the equation by adding the same constants to each side

f(x)-10+b^{2}=\frac{1}{4}(x^{2} +4bx+4b^{2})

Rewrite as perfect squares

f(x)+(b^{2}-10)=\frac{1}{4}(x+2b)^{2}

f(x)=\frac{1}{4}(x+2b)^{2}-(b^{2}-10)

remember that

h=6

so

(x+2b)=(x-6)

2b=-6

b=-3

substitute in the equation

f(x)=\frac{1}{4}(x-6)^{2}-((-3)^{2}-10)

f(x)=\frac{1}{4}(x-6)^{2}+1

therefore

<u>the answer is</u>

b=-3


8 0
4 years ago
Read 2 more answers
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