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VLD [36.1K]
3 years ago
7

1. Explain the direction of gravity’s pull

Physics
2 answers:
STALIN [3.7K]3 years ago
5 0

1).  The direction of gravity's pull between two objects is on the line between their centers of mass. (That's why the "center of mass" is often called the "center of gravity".)

2).  Gravity always exists, and ALL objects with mass pull on ALL other objects with mass.

3).  I am able.

There are no models of the solar system correctly drawn to scale because the size of the objects (sun, planets, moons) are so tiny compared to the space between them, and the distances between the objects are so huge compared to their size.  

If you tried to draw a model to correct scale, and you drew a couple of objects big enough to SEE on the paper, then you'd almost need a piece of paper the size of Texas to show the whole solar system.

-- Pluto's orbit is 8,565 times the size of the sun.

-- If the Moon is the size of a dime, then ...

..... the sun is 1/2 mile away

..... it's 23.5 feet across

..... Pluto's orbit is 19 miles across

NNADVOKAT [17]3 years ago
3 0
1.gravitavtional pull pulls us down towards the ground
2.it exist so we do not float around
3.do not know how to solve 3( hope this help:)
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A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction
Elis [28]

Answer:

(a) 25 m

(b) 75 m

Explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

v=\frac{10}{2}=5m/s\;\cdots(i)

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So, d=vt

From equation (i)

\Rightarrow d=5t\;\cdots(ii)

As the jogger starts from origin, so, the distance, d, also represents the position of the jogger at the time t s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

d=5\times 5=25 m

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

d=5\times 15=75 m

So, the jogger is at a distance of 75 m from the origin.

8 0
3 years ago
A 62.00-cm guitar string under a tension of 70.000 N has a mass per unit length of 0.10000 g/cm. What is the highest resonant fr
quester [9]

Answer:

17,947.02 Hz

Explanation:

length (L) = 62 cm = 0.62 m

tension (T) = 70 N

mass per unit length (μ) = 0.10000 g/cm = 0.010000 kg/m

maximum frequency = 18,000 Hz

f = \frac{n}{2L} x \sqrt{\frac{T}{μ}}

f = \frac{n}{2 x 0.62} x \sqrt{\frac{70}{0.01} }

f = n x 67.47

18,000 = n x 67.47

n = 266.8≈ 266

the 267th overtone is the highest overtone that can be heard by this person, and its frequency would be 26 x 67.47 = 17,947.02 Hz

8 0
3 years ago
An object is positively charged if it has more what​
kkurt [141]

Answer:

An Object is positively charged if it has more Positive Electrons in that object

8 0
3 years ago
A boy is whirling a stone around his head by means of a string. The string makes one complete revolution every second; and the m
Damm [24]

Answer

given,                                                

Tension of string is F                                                  

velocity is increased and the radius is not changed.      

the string makes two complete revolutions every second

consider the centrifugal force acting on the stone          

  = \dfrac{mv^2}{r}                          

now centrifugal force is balanced by tension

T =\dfrac{mv^2}{r}                                

From the above expression we can clearly see that tension is directly proportional to velocity and inversely proportional to radius.

When radius is not changing velocity is increasing means tension will also increase in the string.

8 0
3 years ago
How long will it take, in minutes, for a transformer to transfer 2.3 X 10^6 J of energy from a 120-V circuit to a 345-V circuit
masya89 [10]

Answer:

e

Explanation:

3 0
3 years ago
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