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2 years ago

What is the wavelength of a wave if its frequency is 256 Hz and speed of the wave is 350 m/s?

Physics

1 answer:

DiKsa [7]2 years ago

7 0

Answer:

Explanation:

The equation for this is

$f=\frac{v}{\lambda}$ where f is the frequency, v is the velocity, and lambda is the wavelength. Filling in:

$256=\frac{350}{\lambda}$ and

$\lambda=\frac{350}{256}$ which means that

the wavelength is 1.37 m, rounded to the correct number of significant digits.

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A. molecules are CONSTANTLY moving.

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A ball rolls with a speed of 2.0m/s across a level table that is 1.0m above the floor. Upon reaching the edge of the table it fo

Mekhanik [1.2K]

Answer:0.58 m

Explanation:

The initial velocity of the ball is u = 2.0 m/s

The height of the table is, h = 1.0 m

The ball falls in vertical direction under acceleration due to gravity.

Time taken for ball to hit the floor:

h= ut + 0.5gt² ( from the equation of motion)

1.0 m=2.0 m/s × t+0.5 × 9.8 m/s²× t²

Solving this for t,

t = 0.29 s ( we have neglected the negative value of t)

In the same time, the ball would cover a horizontal distance of :

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Thus, the landing spot is 0.58 m away from the table.

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3 years ago

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A locomotive accelerates a 25-car train along a level track. Every car has a mass of 7.7 ✕ 104 kg and is subject to a friction f

MaRussiya [10]

To solve the problem it is necessary to apply the concepts related to Force of Friction and Tension between the two bodies.

In this way,

The total mass of the cars would be,

$m_T = 25(7.7*10^4)Kg$

$m_T = 1.925*10^6Kg$

Therefore the friction force at 29Km / h would be,

$f=250v$

$f= 250*29Km/h$

$f = 250*29*(\frac{1000m}{1km})(\frac{1h}{3600s})$

$f = 2013.889N$

In this way the tension exerts between first car and locomotive is,

$T=m_Ta+f$

$T=(1.925*10^6)(0.2)+2013.889$

$T= 3.8701*10^5N$

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3 years ago

What is the mechanical advantage of the wheel and axle shown below?

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Answer:

B. 120

Explanation:

24/.2 = 120

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3 years ago

What is the heat capacity of an object at 25.5∘C that absorbs 45 kJ of heat and is heated to 28.2∘C?

sergey [27]

Answer:

16.6 kJ/°C

Explanation:

given,

Amount of heat absorbed = 45 kJ

initial temperature, T₁ = 25.5°C

final temperature, T₂ = 28.2°C

change in temperature = T₂ - T₁

= 28.2 - 25.5 = 2.7° C

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$Heat\ capacity = \dfrac{45\ kJ}{2.7}$

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Heat capacity of the object is equal to 16.6 kJ/°C

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