Answer:
The necessary criterion to validate the PTSD (posttraumatic stress disorder) is criterion A, (one required): the person was exposed to: death, threatened death, actual or threatened serious injury, or actual or threatened sexual violence,one symptom (or more): inability to remember an important aspect of the event, from criterion B, one symptom (or more): wars survivors, persistent and exaggerated negative beliefs about oneself, others, or the world, and persistent negative emotional state.to criterion C: old age abused; persistent distorted cognitions about the cause or consequences of the event.
Explanation:
DSM-5 PTSD diagnosis measures, assesses, or evaluates dissociative subtypes, which causes disconnection from the surrounding world or from oneself.
The DSM-5 manual, for the PTSD diagnosis, includes the DSM-IV/ICD-9 309.81 to the ICD-10 F43.10.
An experienced mental health provider, such as a psychiatrist or psychologist, is generally in charge of the diagnosis.
To be diagnosed with PTSD, an adult must have at least one avoidance symptom re-experiencing symptom for at least 1 month.
Answer:
<em>The rubber band will be stretched 0.02 m.</em>
<em>The work done in stretching is 0.11 J.</em>
Explanation:
Force 1 = 44 N
extension of rubber band = 0.080 m
Force 2 = 11 N
extension = ?
According to Hooke's Law, force applied is proportional to the extension provided elastic limit is not extended.
F = ke
where k = constant of elasticity
e = extension of the material
F = force applied.
For the first case,
44 = 0.080K
K = 44/0.080 = 550 N/m
For the second situation involving the same rubber band
Force = 11 N
e = 550 N/m
11 = 550e
extension e = 11/550 = <em>0.02 m</em>
<em>The work done to stretch the rubber band this far is equal to the potential energy stored within the rubber due to the stretch</em>. This is in line with energy conservation.
potential energy stored = 
==> 
= <em>0.11 J</em>
The choices can be found elsewhere and as follows:
A)There will not be a change.
<span>B)The voltage will decrease by a factor of two. </span>
<span>C)The voltage will increase by a factor of two. </span>
<span>D)The two coils of wire will cancel out the magnetic field. </span>
<span>E)The voltage will be zero.
</span>
I believe the answer is option C. If the magnet is put inside two coils of wire, then the voltage will increase by a factor of two. Hope this answers the question.
Answer:
12 N/cm²
Explanation:
From the question given above, the following data were obtained:
Weight (W) of block = 240 N
Area (A) = 20 cm²
Pressure (P) =?
Next, we shall determine the force exerted by the block. This can be obtained as follow:
Weight (W) of block = 240 N
Force (F) =.?
Weight and force has the same unit of measurement. Thus, we force applied is equivalent to the weight of the block. Thus,
Force (F) = Weight (W) of block = 240 N
Force (F) = 240 N
Finally, we shall determine the pressure on the floor as follow:
Force (F) = 240 N
Area (A) = 20 cm²
Pressure (P) =?
P = F/A
P = 240 / 20
P = 12 N/cm²
Therefore, the pressure on the floor is 12 N/cm².
Answer:
The shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
Explanation:
Given;
coefficient of kinetic friction, μ = 0.84
speed of the automobile, u = 29.0 m/s
To determine the the shortest distance in which you can stop an automobile by locking the brakes, we apply the following equation;
v² = u² + 2ax
where;
v is the final velocity
u is the initial velocity
a is the acceleration
x is the shortest distance
First we determine a;
From Newton's second law of motion
∑F = ma
F is the kinetic friction that opposes the motion of the car
-Fk = ma
but, -Fk = -μN
-μN = ma
-μmg = ma
-μg = a
- 0.8 x 9.8 = a
-7.84 m/s² = a
Now, substitute in the value of a in the equation above
v² = u² + 2ax
when the automobile stops, the final velocity, v = 0
0 = 29² + 2(-7.84)x
0 = 841 - 15.68x
15.68x = 841
x = 841 / 15.68
x = 53.64 m
Thus, the shortest distance in which you can stop the automobile by locking the brakes is 53.64 m
