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kvasek [131]
2 years ago
6

Using a material that is ‘Ohmic’ (it follows Ohm’s Law), you make a circuit using wire, a battery, and a resistor. After measuri

ng V, I, and R across the circuit, you switch out the original resistor with one 3 times more resistive. When you measure V, I, and R again, how will the new values compare to the old?
Physics
1 answer:
victus00 [196]2 years ago
5 0

When the original resistor is replaced with 3 times more resistive material, the resistance of the circuit increases by factor of 3 and  the current flowing in the cirucit decreases by a factor 3.

<h3>Ohm's law</h3>

Ohm's law states that, the current flowing in a conductor is directly proportional to the potential across the conductor.

V = IR

where;

  • I is the current in the circuit
  • V is voltage
  • R is the resistance

When the resistance increases, the current flowing in the circuit decreases.

When the original resistor is replaced with 3 times more resistive material, the resistance of the circuit increases by factor of 3 and  the current flowing in the cirucit decreases by a factor 3.

Learn more about ohm's law here: brainly.com/question/231741

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A gas in a cylinder is held at a constant pressure of 1.80 * 105 Pa and is cooled and compressed from 1.70 m3 to 1.20 m3. The in
Lilit [14]

Answer:

The work done is W=-0.9*10^5J and it is negative because the exterior is doing work on the gas.

The value of the heat flow is Q=2.3*10^5J and is directed out of the gas, as this is being cooled and compressed.

Explanation:

The work done by the gas can be written as

W=\int\limits^ {V_{c}}_{V_{h}}{P}\, dV

and all the data is given in the problem, so

W=P(V_{c}-V_{h})=-0.9*10^5J

is the work necessary to compress the gas in the cylinder, wich is negative because the exterior is doing work on the gas.

Now, from first law of thermodynamics, we have that

\Delta U=Q+W

<em>where \Delta U is the internal energy difference, W is the calculated work, and Q is the heat flow that we wish to know</em>, then

Q=\Delta U-W=1.4*10^5J+0.9*10^5J=2.3*10^5J

And the direction of the heat flow is outside of the gas, as it is being cooled and compressed.

Finally, it doesn't matter whether the gas is ideal or not, because we never use the Ideal Gas hypotesis, that PV=nRT, and P is constant.

6 0
3 years ago
Select all that apply. The resistance to an object being pulled over a surface is called _____. starting friction, sliding frict
jok3333 [9.3K]
That is kinetic friction.
8 0
4 years ago
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A particle of mass 3m is located 1.00 m from a particle of mass m. (a) Where should you put a third mass M so that the net gravi
Airida [17]

Explanation:

It is given that net gravitational force on M is exactly equal to zero. Hence, distance to M from the bigger mass is 3m. Therefore, expression for net force will be as follows.

           F_{net} = F_{1} + F_{2} = 0  

So,  

          \frac{-G(3m)(M)}{x^{2}} + \frac{G(m)(M)}{(1 - x)^{2}} = 0

The first term is negative as the third mass is located between the other two masses. This means that 3 m will be pulling it leftwards (negative x direction) and m will be pulling it rightwards (positive x direction).

      \frac{G(m)(M)}{(1 - x)^{2}} = \frac{G(3m)(M)}{(x)^{2}}

On dividing both sides of the equation by G.m.M, we get the following.

      \frac{1}{(1 - x)^{2}} = \frac{3}{x^{2}}

               x^{2} = 3 - 6x + 3x^{2}

                    0 = 3 - 6x + 2x^{2}

Using the formula, \frac{-b \pm \sqrt{(b)^{2} - 4ac}}{2a}   the value of x comes out to be equal to +2.37 (not usabale) and -0.634 (usable).

Hence, we can conclude that the third mass will be located 0.634 meters away from the 3 m mass.

7 0
3 years ago
What are the4 spheres on earth
Anon25 [30]

Answer:

northen henisphere,southern hemisphere, Eastern hemisphere, Western hemisphere.

5 0
3 years ago
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Which of the outer planets is MOST like Earth? How?
Over [174]

Answer:

It is not impossible to answer the question, my apologies for “discrediting” the answer it would have to be Venus, the outer planet most similar to earth.

Explanation:

Venus is very similar to earth, as many studies, research, factual intellectual based concepts - the size, shape, surface gravity, average density, mass, average days of 24 hours, season changes similar to earth, and tilted axis. As well as similar climate make Venus the most accurate answer.

Hope this helps! Thank you for your time.

5 0
4 years ago
Read 2 more answers
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