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frosja888 [35]
3 years ago
6

1. A television set falls from rest from a bridge 100m above the river surface.

Physics
1 answer:
Stolb23 [73]3 years ago
3 0

Answer:

It would break because how fast and how tall the fall is because at a certain hight water can act like a solid and break your body/bones or you could die

its a do or die situation

Explanation:

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If a proton with velocity v is inside a uniform magnetic field, the work done on the proton by the magnetic field is greater tha
Kipish [7]

Answer:

ZERO

Explanation:

As we know that force due to magnetic field on moving charge is given by

\vec F = q(\vec v \times \vec B)

now here we can say that the force due to magnetic field is always perpendicular to the velocity and it is also perpendicular to the magnetic field.

So we can say that

\vec F. \vec v = 0

so power due to magnetic field is always zero

which shows that rate of work done by magnetic field on moving charge is zero

so here the work done by magnetic field is always zero

7 0
4 years ago
What is the weight (in N) of a 107kg object
swat32

1048.6 N. Kg x 9.8 m/s^2 gives you Newtons

8 0
3 years ago
Read 2 more answers
Water can also evaporate from plants in a process called ____?
BigorU [14]
The answer your looking for my friend is called evaporation 
5 0
4 years ago
The harmonic series from a long tube is given below. Isthis tube acting as an open-pipe resonator or a closed-piperesonator? Exp
Ira Lisetskai [31]

Answer:

We know that what we hear as a single sound or pitch when someone is speaking (for example, when making the sound [i]) is really a fundamental frequency 基頻 (determined by how many times the vocal folds vibrate in one second, and measured in cycles per second [cps], or hertz 赫 [Hz]; named after the German physicist Heinrich Rudolf Hertz), plus a whole series of harmonics 諧音 (often called 泛音 on stringed instruments) or overtones 倍音. These terms overlap in meaning, but: "harmonic" includes the fundamental frequency and all of the overtones above it, while "overtones" include all frequencies greater than the fundamental frequency.

Explanation:

    The harmonics are multiples of the fundamental frequency. So if the fundamental frequency is 100 Hz, the higher harmonics will be 200 Hz, 300 Hz, 400 Hz, 500 Hz, and so on. If the fundamental frequency were 220 Hz, the harmonics would be 440 Hz, 660 Hz, 880 Hz, and so on. In terms of intervals on the scale, we hear a base tone, its octave (eight notes up), then a note that is a twelfth up, i.e. a perfect fifth above the octave above the starting pitch, then a note two octaves up from the starting pitch, then one that is a major third above that, and on and on. If the starting pitch is middle C (C'; 256 Hz), the overtones are C" (512 Hz), G" (768 Hz): C''' (1024 Hz), E''' (1280 Hz), G''' (1536 Hz), B♭''' (1792 Hz), and so on. (Actually, your piano is tuned somewhat differently, because it uses "equal temperament". (The difference between "just intonation" and equal temperament are demonstrated in this video. But that's another story!)

   We normally don't hear the harmonics as separate tones, first of all because they have an increasingly lower amplitude than the fundamental frequency the higher up they go. The harmonics are nevertheless present in the sound, and they add a lot of richness to the sound of a human voice, a musical instrument, and many other kinds of sounds. Without them a voice would sound thin and uninteresting.

    But where do the harmonics come from, or more precisely, how are they produced? If you play the guitar, you are probably familiar with harmonics and how to produce them, even if you don't fully understand how they work. A guitar string works something like the vocal folds when it vibrates, and is a little easier to illustrate and visualize. So we will first look at how a guitar string vibrates in order to understand by analogy how the vocal folds do. Look at the animations at the bottom of this page, from the University of Salford in Manchester, UK, under Standing waves:

7 0
3 years ago
Read 2 more answers
A satellite, orbiting the earth at the equator at an altitude of 400 km, has an antenna that can be modeled as a 1.76-m-long rod
ivann1987 [24]

Answer:

The inducerd emf is 1.08 V

Solution:

As per the question:

Altitude of the satellite, H = 400 km

Length of the antenna, l = 1.76 m

Magnetic field, B = 8.0\times 10^{- 5}\ T

Now,

When a conducting rod moves in a uniform magnetic field linearly with velocity, v, then the potential difference due to its motion is given by:

e = - l(vec{v}\times \vec{B})

Here, velocity v is perpendicular to the rod

Thus

e = lvB           (1)

For the orbital velocity of the satellite at an altitude, H:

v = \sqrt{\frac{Gm_{E}}{R_{E}} + H}

where

G = Gravitational constant

m_{e} = 5.972\times 10^{24}\ kg = mass of earth

R_{E} = 6371\ km = radius of earth

v = \sqrt{\frac{6.67\times 10^{- 11}\times 5.972\times 10^{24}}{6371\times 1000 + 400\times 1000} = 7670.018\ m/s

Using this value value in eqn (1):

e = 1.76\times 7670.018\times 8.0\times 10^{- 5} = 1.08\ V

5 0
3 years ago
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