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solniwko [45]
3 years ago
11

A model car is 8 inches long and 5.2

Mathematics
1 answer:
Sphinxa [80]3 years ago
7 0
Use proportions here - 8/5.2 = 96/width of actual car. using cross multiplication, 5.2*96 = 8x. this gives you 499.2 = 8x. divide both sides by eight to get x=62.4. the width of the actual car is 62.4 inches.
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How do i write this ?
Makovka662 [10]

Answer:

1\frac{5}{9\\}

Step-by-step explanation:

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The prism shown has a volume of 35cm³. Work out the height of the triangular cross section. The length going back is 7cm and the
Gre4nikov [31]

Answer:

2.5 cm

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3 0
3 years ago
Steel loading ramps are used to load a lawn mower onto a truck bed 37.5 inches above the ground. If the ramp make a 30° angle wi
scoray [572]

Answer:

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Step-by-step explanation:

Please find the attachment.

Let L be the length of the ramp in feet.  

We have been given that steel loading ramps are used to load a lawn mower onto a truck bed 37.5 inches above the ground. The ramp make a 30° angle with the ground.

We can see from our attachment that ramp and truck bed forms a right triangle with ground. The truck bed is opposite side and length of ramp is hypotenuse of our given angle.

Since we know that Sine relates the opposite and hypotenuse of a right triangle, so we will use Sine to solve for L.

\text{Sine}=\frac{\text{Opposite}}{\text{Hypotenuse}}

Upon substituting our given values in above formula we will get,

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L=\frac{37.5}{\text{Sin(30)}}

L=\frac{37.5}{0.5}

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Therefore, the length of the ramp is 75 inches.

Let us convert the length of ramp in feet.

1 feet = 12 inches.

\text{75 inches}=\frac{75\text{ inches}}{\frac{12\text{ inches}}{\text{feet}}}

\text{75 inches}=\frac{75\text{ inches}}{12}\times \frac{\text{ feet}}{\text{inches}}

\text{75 inches}=\frac{75}{12}\times\text{ feet}

\text{75 inches}=6.25\text{ feet}

Therefore, the length of the ramp is 6.25 feet.

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