A1. 12 i.e option D
A2. 3n-7 i.e option A
A3. -6n+20 i.e option D
A4. -70 i.e option C
Step-by-step explanation:
aₙ = a₁ + (n - 1) × d
aₙ = the nᵗʰ term in the sequence
a₁ = the first term in the sequence
d = the common difference between terms
Using the above formula to solve the first part, we have :
For the second part, we have :
For the third part, we have :
For the fourth part, we have :
The decrease in the value of the toy is $9.25 if you subtract $ 0.75 from $10.00 then you get $9.25 so it's $9.25 cheaper
Answer:
D) Survey 100 randomly selected students from the school
Step-by-step explanation:
This gives an equal chance to everybody, so it's not biased and it is of everybody that goes to his school. A is only the people on the football team so its not students in his school. Walking to school has nothing to do with the survey topic and so thats also definitely not it. C again doesn't give a fair chance to everybody, so it would be possible to get an accurate, unbiased answer. D is definitely your answer!
I hope that helps!!
Have an awesome day! :)
it equals <span>(−<span>12</span>)</span> because <span><span>cos<span>(<span>60∘</span>)</span></span>=<span>12</span></span>
Explanation:
The reference angle for <span>240∘</span> is <span>60∘</span> (since <span><span>240∘</span>=<span>180∘</span>+<span>60∘</span></span>)
<span>60∘</span> is an angle of one of the standard triangles with
<span><span>cos<span>(<span>60∘</span>)</span></span>=<span>12</span></span>
<span>240∘</span> is in the 3rd quadrant so (either by CAST or noting that the "x-side" of the associate triangle is negative)
<span><span>cos<span>(<span>240∘</span>)</span></span>=−<span>cos<span>(<span>60∘</span>)</span></span></span>
<span><span>cos<span>(<span>240∘</span>)</span></span>=−<span><span>12</span></span></span>
<span>The mean would typically be the best measure of determining the success of this business. Barring the presence of any outlier values, finding the average number of cameras sold per period (week, month, year, etc.) would give a better picture than the range or mode. The median could be used, but it is a bit less descriptive than the median in this instance.</span>
