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uysha [10]
3 years ago
15

The area of a rectangle is 144 square centimeters. The width is 9 centimeters. Which of the following statements is true? Select

all that apply. A. The length is 3 times the width. B. The length is 63 centimeters. C. The length is less than 2 times the width. D. The perimeter is 50 centimeters. E. The rectangle is a square since its length and width are equal.
Mathematics
2 answers:
Ket [755]3 years ago
6 0

Answer:

Option C and D are correct.

Step-by-step explanation:

Area of rectangle = 144 cm^2

Width of rectangle = 9 cm

Length of rectangle = ?

We know,

Area of rectangle = Length * Width

144 = Length * 9

144/9 = Length

=> length = 16 cm

Option A is incorrect as 3 times width = 3* 9 = 27 but our length = 16 cm

Option B is incorrect as length = 16 cm and not 63 cm

Option C is correct as Length < 2(Width)

=> 16 < 2(9) => 16 < 18 which is true.

Option D is correct.

Perimeter = 2(Length + Width)

Perimeter = 2(16+9)

Perimeter = 50 cm

Option E is incorrect as Length ≠ Width

Pavel [41]3 years ago
4 0

Answer:

C. The length is less than 2 times the width.

D. The perimeter is 50 centimeters.

Step-by-step explanation:

The area of the rectangle is given as 144 square centimeters and its width is 9 centimeters. The formula for the area of a rectangle is given as;

Area = length*width

144 = length*9

length = 144/9

length = 16 centimeters

A. The length is 3 times the width.

3 times the width; 3*9 = 27 cm which is not equal to 16. Hence this statement is false.

B.The length is 63 centimeters.

This statement is also false since the length is 16 cm

C.The length is less than 2 times the width.

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Answer:

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Step-by-step explanation:

see the attached figure with letters to better understand the problem

step 1

In the right triangle ACD

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Applying the Pythagorean Theorem

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substitute the given values

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AC=\sqrt{320}\ units

simplify

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step 2

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substitute the given values

cos(\angle CAD)=\frac{16}{8\sqrt{5}}

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step 3

In the right triangle ABC

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step 4

Find the value of x

In this problem

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so

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Multiply in cross

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step 5

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substitute the given values

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