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Aneli [31]
3 years ago
15

A 20 year-old patient presented to the hospital with a history of bloody stools for three weeks' duration. the patient was prepp

ed for a sigmoidoscopy. the sigmoidoscope was passed without difficulty to about 40 cm. the entire mucosal lining was erythematosus. there was no friability of the overlying mucosa and no bleeding noted. no pseudo polyps were identified. biopsies were taken at about 30 cm; these were thought to be representative of the mucosa in general. the scope was retracted; no other abnormalities were seen. what cpt® and icd-10-cm codes are reported?
Biology
1 answer:
kirill [66]3 years ago
7 0
The answer is 45331, K92.1. CPT® code for a sigmoidoscopy with single or various biopsies is accounted for 45331. This is recorded under Sigmoidoscopy/Biopsy. Symptomatic sigmoidoscopy is constantly packaged with a surgical sigmoidoscopy when both are performed in a similar agent session. The ICD-10-CM code for bleeding stools is found in the Index to Diseases and Injuries under Blood/in/defecation or Hematochezia or Melena and coded K92.1. At the point when a patient comes in with a GI side effect and no conclusive analysis is reported for the indication.
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In chickens, comb shape is determined by genes at two loci (R, r and P, p). A walnut comb is produced when at least one dominant
Ivenika [448]

Answer and Explanation:

<em><u>Available data</u></em>:

  • Comb shape is determined by genes at two loci (R, r and P, p).
  • The walnut comb genotype is R_P_.
  • The rose comb genotype is R_pp.
  • The pea comb genotype is rrP_.
  • The single genotype is rrpp.

a. <em>Walnut crossed with single produces 1 walnut, 1 rose, 1 pea, and 1 single offspring: </em>

Parental)             RrPp       x          rrpp

Gametes)   RP   Rp   rP   rp     rp   rp   rp   rp

Punnet Square)      RP       Rp     rP        rp

                     rp   <em>RrPp    Rrpp   rrPp   rrpp</em>

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

                     rp    RrPp    Rrpp   rrPp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

b. <em>Rose crossed with pea produces 20 walnut offspring</em>.

Parental)              RRpp       x          rrPP

Gametes)   Rp   Rp   Rp   Rp     rP   rP   rP   rP

Punnet Square)      Rp       Rp     Rp        Rp

                     rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp  RrPp

                    rP    RrPp    RrPp   RrPp   RrPp

                     rP    RrPp    RrPp   RrPp   RrPp

F1 phenotype: 100% walnut.

F1 genotype: 16/16 RrPp.

c. <em>Pea crossed with single produces 1 single offspring</em>.

This is not possible, because the pea genotype involves <u>at least</u> one dominant allele P. There are two possible crosses: <em>rrPp x rrpp</em>, which must produce half of the progeny pea and the other half single, or <em>rrPP x rrpp</em> which produce a whole pea progeny with no single offspring.  

Parental)              rrPp       x          rrpp

Gametes)   rP   rp   rP   rp     rp   rp   rp   rp

Punnet Square)     rP       rp       rP      rp

                     rp   <em>rrPp    rrpp   rrPp   rrpp</em>

                    rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

                     rp    rrPp    rrpp   rrPp   rrpp

F1 phenotype: 50% pea, and 50% single.

F1 genotype: 8/16 rrPp, 8/16 rrpp.

d. <em>Rose crossed with pea produces 2 walnut, 1 single, and 1 pea offspring</em>.

This is not possible, because having one of the parents with a rose phenotype  involves <u>at least one R allele</u>, which means that <u>there must be rose phenotype</u> in the progeny.

Parental)             Rrpp       x          rrPp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)     Rp       Rp       rp      rp

                     rP  <em> RrPp </em>   RrPp  <em> rrPp</em>   rrPp

                     rP   RrPp    RrPp   rrPp   rrPp

                     rp    <em>Rrpp</em>    Rrpp   <em>rrpp </em>  rrpp

                     rp   Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 25% walnut, 25% rose, 25% pea, and 25% single.

F1 genotype: 4/16 RrPp, 1/16 Rrpp, 4/16 rrPp, 4/16 rrpp.

e. <em>Rose crossed with single produces 31 rose offspring</em>.

Parental)              RRpp       x          rrpp

Gametes)   Rp   Rp   Rp   Rp     rp   rp   rp   rp

Punnet Square)     Rp       Rp       Rp      Rp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

                     rp    Rrpp    Rrpp   Rrpp   Rrpp

F1 phenotype: 100% rose (31 individuals equal 100% of the progeny).

F1 genotype: 16/16 Rrpp.

f. <em>Rose crossed with single produces 10 rose and 11 single offspring.</em>

Parental)              Rrpp       x          rrpp

Gametes)   Rp   Rp   rp   rp     rP   rP   rp   rp

Punnet Square)      Rp       Rp       rp      rp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

                     rp    Rrpp    Rrpp   rrpp   rrpp

F1 phenotype: 50% rose, 50% single.

F1 genotype: 8/16 Rrpp, 8/16 rrpp.

3 0
3 years ago
Why do plants of the fields become yellowish?​
aliina [53]

Answer:

Poor drainage or improper watering

Explanation:

Water issues — either too much or too little — are the leading reason behind yellow leaves. In overly wet soil, roots can't breathe. They suffocate, shut down and stop delivering the water and nutrients plants need. Underwatering, or drought, has a similar effect.

5 0
3 years ago
What is goose flesh​
Alekssandra [29.7K]

Answer:

<em>Goose Flesh</em><em> also known as </em><em>Goose Bumps</em><em> also known as</em><em> Cutis Anserina (scientific term).</em><em> It is a temporary change of skin. The skin becomes rougher due to fear, cold, excitement, etc. Small bumps appear on the surface of the skin because the arrector pili muscles contract. </em>

Hope this helped

:)

6 0
3 years ago
Distinguish between the characteristics of an unweathered rock and those of a highly weathered rock
Katarina [22]
I would think that an unweathered rock would be jagged while a weathered rock would be smooth because of water/wind or what ever weathered it.
3 0
3 years ago
The destructive force of waves is not felt while they are out at sea, in the open ocean, but it is
Vedmedyk [2.9K]

The destructive force of the wave is not felt while they are out at the sea but it is felt when they approach the shore.

<u>Explanation:</u>

When the waves are out in the ocean they are in deeper waters. Once they move towards the shore they approach shallow waters. This movement causes shoaling of the waves by which its amplitude increases.

When the wave reaches the shore its leading edge gets slowed down by coming in contact with the beach floor but its trailing edge which is still in deep water still moves rapidly. The wave thus gets compressed and its wavelength decreases. The amplitude of the wave then increases rapidly making the wave destructive.

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