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Arisa [49]
3 years ago
15

If line ML is a midsegment of triangle IJK, find KJ

Mathematics
2 answers:
Inga [223]3 years ago
8 0
<span>A midsegment connecting two sides of a triangle is parallel to the third side and is half as long.

</span>ML= \frac{1}{2}KJ \ \ \to \ \  KJ = 2ML = 2*12 = 24<span>
</span>
laila [671]3 years ago
4 0
So what we're dealing with here is a similar triangle situation. Since ML is a midsegment, that means that IL and LJ are congruent. So, IL=LJ=13. This means that the whole side IJ is 26 (13+13=26). We also know that triangle IML and triangle IKJ are similar triangles, so their sides are proportional. This means that we can set up the ratio:
12/13 = x/26
and solve for x.
After multiplying 26 to both sides of the equation, we find that x=24, so KJ=24.
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Answer:

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Step-by-step explanation:

Hello!

When all other things remain the same, which of the following statements about the width of the interval is correct?

A. The interval will be narrower if 15 men are used in the sample.

B. The interval will be wider if 15 men are used in the sample.

C. The interval will be narrower if 5 men are used in the sample.

D. The interval will be narrower if the level is increased to 99% confidence.

E. The interval will be wider if the level is decreased to 90% confidence.

Consider that the variable of interest "Xd: Difference between the peak power of a cyclist before training and after training" has a normal distribution. To construct the confidence interval for the population mean of the difference you have to use a pooled t-test.

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The margin of error of the interval is:

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1) The sample size changes, all other terms of the interval stay the same.

As you can see the margin of error and the sample size (n) have an indirect relationship. This means, that when the sample size increases, the semiamplitude decreases, and when the sample size decreases, the semiamplitude increases.

↓d= t_{n-1;1-\alpha /2} * (Sd/↑n)

↑d= t_{n-1;1-\alpha /2} * (Sd/↓n)

Correct option: A. The interval will be narrower if 15 men are used in the sample.

2) The confidence level has a direct relationship with the semiamplitude of the interval, this means that when the confidence level increases, so do the semiamplitude, and if the level decreases, so do the semiamplitude:

↓d= ↓t_{n-1;1-\alpha /2} * (Sd/n)

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I hope it helps!

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