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maxonik [38]
2 years ago
14

Describe an estimate that Felicia might do in her head while driving to decide how many gallons of gas she needs to make it to t

he gas station at the other end.
Mathematics
1 answer:
sveticcg [70]2 years ago
7 0
There's not enough info to answer this question. How far is the other gas station? And how many gallons of gas does she use for the distance?
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babymother [125]

Answer:

87°

Step-by-step explanation:

it can be seen directly

if you want angle AOD

it's 78°

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3 years ago
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Mrs.Davis bought 6 pounds of grapes for 18 dallors at this rate how much would 72 ounces of grapes have cost
harkovskaia [24]

Answer:

Cost of 72 ounces of grapes is $13.5


Step-by-step explanation:

In order to solve his problem, we first need to get all the values in the same units.

  1 pound = 16 ounces

∴ 6 pounds= 16×6 = 96 ounces

Now by unitary method, we solve the question as follows:

price of 96 ounces of grapes = $ 18

price of 1 ounce of grapes = $ (18÷96)

∴ price of 72 ounces of grapes = $ [(18÷96)×72]

= (0.1875×72) =  $ 13.5

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3 years ago
Help please i really need it asap
Varvara68 [4.7K]
The expression coud be re written:

12x²y/2xy + 6xy/2xy + 4x²/2xy . Simplify numerator & denominator whenever it is possible:

6x-3+2x/y
3 0
2 years ago
Can someone can help me plssssssss
mario62 [17]

Answer:

Rectangle

Step-by-step explanation:

Because the floor is made of floor

5 0
3 years ago
Before the pandemic cancelled sports, a baseball team played home games in a stadium that holds up to 50,000 spectators. When ti
spayn [35]

Answer:

(a)D(x)=-2,500x+60,000

(b)R(x)=60,000x-2500x^2

(c) x=12

(d)Optimal ticket price: $12

Maximum Revenue:$360,000

Step-by-step explanation:

The stadium holds up to 50,000 spectators.

When ticket prices were set at $12, the average attendance was 30,000.

When the ticket prices were on sale for $10, the average attendance was 35,000.

(a)The number of people that will buy tickets when they are priced at x dollars per ticket = D(x)

Since D(x) is a linear function of the form y=mx+b, we first find the slope using the points (12,30000) and (10,35000).

\text{Slope, m}=\dfrac{30000-35000}{12-10}=-2500

Therefore, we have:

y=-2500x+b

At point (12,30000)

30000=-2500(12)+b\\b=30000+30000\\b=60000

Therefore:

D(x)=-2,500x+60,000

(b)Revenue

R(x)=x \cdot D(x) \implies R(x)=x(-2,500x+60,000)\\\\R(x)=60,000x-2500x^2

(c)To find the critical values for R(x), we take the derivative and solve by setting it equal to zero.

R(x)=60,000x-2500x^2\\R'(x)=60,000-5,000x\\60,000-5,000x=0\\60,000=5,000x\\x=12

The critical value of R(x) is x=12.

(d)If the possible range of ticket prices (in dollars) is given by the interval [1,24]

Using the closed interval method, we evaluate R(x) at x=1, 12 and 24.

R(x)=60,000x-2500x^2\\R(1)=60,000(1)-2500(1)^2=\$57,500\\R(12)=60,000(12)-2500(12)^2=\$360,000\\R(24)=60,000(24)-2500(24)^2=\$0

Therefore:

  • Optimal ticket price:$12
  • Maximum Revenue:$360,000

3 0
3 years ago
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