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sattari [20]
3 years ago
8

Rewrite the equation below in standard form.

Mathematics
1 answer:
eduard3 years ago
3 0
Rewrite the equation below in standard form.
-3x+6y=12


C. -x+2y=4

if you take each term and divide them by 3 you will get the c
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Which of the following is a solution to 2cos2x − cos x − 1 = 0?
Pavel [41]

Answer:

Option A is correct.

Solution for the given equation is, x = 0^{\circ}

Step-by-step explanation:

Given that : 2\cos^2x -\cos x -1 =0

Let \cos x =y

then our equation become;

2y^2-y-1= 0           .....[1]

A quadratic equation is of the form:

ax^2+bx+c =0.....[2] where a, b and c are coefficient and the solution is given by;

x = \frac{-b\pm \sqrt{b^2-4ac}}{2a}

Comparing equation [1] and [2] we get;

a = 2 b = -1 and c =-1

then;

y = \frac{-(-1)\pm \sqrt{(-1)^2-4(2)(-1)}}{2(2)}

Simplify:

y = \frac{ 1 \pm \sqrt{1+8}}{4}

or

y = \frac{ 1 \pm \sqrt{9}}{4}

y = \frac{ 1 \pm 3}{4}

or

y = \frac{1+3}{4} and y = \frac{1 -3}{4}

Simplify:

y = 1 and y = -\frac{1}{2}

Substitute y = cos x we have;

\cos x = 1

⇒x = 0^{\circ}

and

\cos x = -\frac{1}{2}

⇒ x = 120^{\circ} \text{and} x = 240^{\circ}

The solution set:  \{0^{\circ}, 120^{\circ} , 240^{\circ}\}

Therefore, the solution for the given equation  2\cos^2x -\cos x -1 =0 is, 0^{\circ}





8 0
3 years ago
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fgiga [73]

Answer: I believe its 24.

5 0
3 years ago
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I think isn't anyone of these alternatives because if we put number 15 in the place of y it is x-y=30. X-15=30
X=30+15=45.
X=45
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3 years ago
What is the value of x
damaskus [11]

Answer:

Step-by-step explanation:

115+94+107+2x=360 degree(sum of interior angles of four angles is always 360 degree)

316+2x=360

2x=360-316

x=44/2

x=22 degree

6 0
3 years ago
How many different kinds of shapes are used to create the faces on this three-dimensional model?
love history [14]

Answer:

2 kinds of shapes are used to create the faces on this three-dimensional model.

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