Answer:
176 199 pounds
Step-by-step explanation:
To answer this it is first useful to find the proportionality constant.
F= kx
8080 pounds = k.88 in
k = 91.81 pound/inch
So what force is required to stretch the spring to 1919 inches?
F = kx
= 91.81 pound/inch * 1919 inches
= 176 199 pounds
It is worth noting that this force seems rather large and the spring might have long reached its elastic limit
Answer:
Step-by-step explanation:
subtract 1 from both sides
-6x<-17-1
simplify
-6x<-18
divide by 6 on both sides
x>3
You multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get 3x^2y
I think it's x^4.
(Honestly, I feel 90% positive of this answer, so maybe just get one more opinion!)
(f+g) (n) = (–5n +1 ) + (- 6n +2) = –11n +3
(f+g) (n) = –11n +3
(f+g) (–2) = – 11 (–2) +3 = 22 +3 = 25
I hope I helped you^_^
