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3 years ago

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While dragging a crate a workman exerts a force of 628 N. Later, the mass of the crate is increased by a factor of 3.8. If the w

orkman exerts the same force, how does the new acceleration compare to the old acceleration?

2 answers:

Delvig [45]3 years ago

6 0

Force applied = F = 628 N
<span>Acceleration = a m/s² </span>
<span>Newton's 2nd law of motion : F = Ma </span>
<span> a = F/M -------- (1) </span>
<span>New mass of the crate = M1 = 3.8M kg </span>
<span>New acceleration = a1 = F/M1 = F/(3.8 M) ----- (2) </span>
<span>a1/a = {F/(3.8M)}/(F/M) = 1/3.8 = 10/38 = 5/19 ------- Answer</span>

Alja [10]3 years ago

5 0

Answer:

The acceleration would decrease by a factor of 3.8.

Explanation:

Force = mass x acceleration

F = ma

If the mass is increased by a factor of 3.8. New mass = 3.8 m

If the same force is exerted, then acceleration is inversely proportional to mass and it changes by:

$\frac {3.8 m}{m} = \frac{a} {a'}\\ \Rightarrow a' = \frac {a} {3.8}$

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