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Mrac [35]
3 years ago
15

A scientist found a new bacteria in a hot water sulfur spring that uses sulfur as a source of energy instead sunlight. What kind

of organism could it be?
Physics
1 answer:
Sergio039 [100]3 years ago
5 0
Chemosynthetic bacteria or chemoautotropic bacteria is the new bacteria that was found by scientists in a hot water sulfur spring that uses sulfur as a source of energy instead of sunlight. This kind of bacteria can survive at a higher temperature than most organisms can.The bacteria uses the toxic hydrogen sulfide to produce organic materials by the process of chemosynthesis. These bacteria are a source of life for several other organisms that flourish in such conditions. The bacteria grows and forms a thick mat and this attracts several other organisms as the bacteria becomes a source of food.
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3 years ago
Explain how tidal forces are causing Earth to slow down.
dybincka [34]

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6 0
3 years ago
Consider an optical cavity of length 40 cm. Assume the refractive index is 1, and use the formula for Icavity vs wavelength to p
Bad White [126]

Answer:

Diode Lasers  

Consider a InGaAsP-InP laser diode which has an optical cavity of length 250  

microns. The peak radiation is at 1550 nm and the refractive index of InGaAsP is  

4. The optical gain bandwidth (as measured between half intensity points) will  

normally depend on the pumping current (diode current) but for this problem  

assume that it is 2 nm.  

(a) What is the mode integer m of the peak radiation?  

(b) What is the separation between the modes of the cavity? Please express your  

answer as Δλ.  

(c) How many modes are within the gain band of the laser?  

(d) What is the reflection coefficient and reflectance at the ends of the optical  

cavity (faces of the InGaAsP crystal)?  

(e) The beam divergence full angles are 20° in y-direction and 5° in x-direction  

respectively. Estimate the x and y dimensions of the laser cavity. (Assume the  

beam is a Gaussian beam with the waist located at the output. And the beam  

waist size is approximately the x-y dimensions of the cavity.)  

Solution:  

(a) The wavelength λ of a cavity mode and length L are related by  

n

mL

2

λ = , where m is the mode number, and n is the refractive index.  

So the mode integer of the peak radiation is  

1290

1055.1

10250422

6

6

= ×

××× == −

−

λ

nL

m .  

(b) The mode spacing is given by nL

c f 2

=Δ . As

λ

c f = , λ

λ

Δ−=Δ 2

c f .  

Therefore, we have nm

nL f

c

20.1

)10250(42

)1055.1(

2 || 6

2 2 26

= ×××

× ==Δ=Δ −

− λλ λ .  

(c) Since the optical gain bandwidth is 2nm and the mode spacing is 1.2nm, the  

bandwidth could fit in two possible modes.  

For mode integer of 1290, nm

m

nL 39.1550

1290

10250422 6

= ××× ==

−

λ

Take m = 1291, nm

m

nL 18.1549

1291

10250422 6

= ××× ==

−

λ

Or take m = 1289, nm

m

nL 59.1551

1289

10250422 6

= ××× ==

−

λ .

Explanation:

8 0
3 years ago
What is the safest way to enter a body of water? Enter with you feet first. Dive in.
zimovet [89]

Answer: feet first

Explanation:

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4 0
2 years ago
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A low-pass first-order instrument has a time constant of 20 ms. find the frequency, in hertz, of the input at which the output w
Vladimir [108]
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8 0
3 years ago
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