Since the y axis stayed consistent, we can assume it did not move at all.
(So your answer would be A)
Answer:
Work done in all the three cases will be the same.
Explanation:
1) The free falling body has only one force acting on it, the gravitational force. The work done on the body = mgH (Gravitational potential energy)
2) There are two forces acting on the body going down on a frictionless inclined plane - gravity and the normal force. The gravitational potential energy will be the same. The work done due to the normal force is zero, since the direction of the force is perpendicular to the displacement. Hence, total work done on the body = mgH
3) In the case of the body swinging on the end of a string, the change in gravitational potential enrgy will once again be the same since difference in height is H. The additional force on the body is the tension due to the string. But the work done due to this force is <em>zero, </em>since the displacement of the body is perpendicular to the tension. Therefore, the total work done on the body is once again mgH.
Answer:
correct answer is option (A) 0.012 mol
Explanation:
Given:
Molar mass of the platinum, M = 195 g/mol
Mass of the platinum in the ring, m = 2.3 g
Now,
the number of moles (n) is calculated as :
thus,
on substituting the respective values in the formula, we get
or
n = 0.01179 mol ≈ 0.012 mol
Hence, the correct answer is option (A) 0.012 mol
D. The density of the sir increases and the air rises.
When coming in contact with the kettle, it becomes hot, it expands and rises up, due to lesser density as compared to the surrounding air.
Answer:
57.4 m/s
Explanation:
Component of vectors parallel to the ground = v sin(titha)
= 100×sin35
= 57.4 m/s
You can read further:
https://www.mathalino.com/reviewer/engineering-mechanics/components-of-a-force