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antoniya [11.8K]
4 years ago
5

Ions can cross a membrane without the help of an integral membrane protein. True or False

Physics
1 answer:
denis-greek [22]4 years ago
6 0

Answer:

False

Explanation:

ionic particles, which are hydrophilic, cannot easily cross a membrane. Very small polar molecules, such as water, can cross via simple diffusion due to their small size. Charged atoms or molecules of any size cannot cross the cell membrane via simple diffusion as the charges are repelled. Because these ions can cross the cell membrane, their movement is restricted to protein channels and specialized transport mechanisms in the membrane.

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What is the resultant displacement of the two vectors below
NeX [460]

Answer:

The resultant displacement is 5.8 cm, 31° South of the West axis ⇒ 4th

answer

Explanation:

<u><em>A resultant vector</em></u> is the combination of two or more single vectors

If the two vectors are perpendicular, then

<em><u>The magnitude</u></em> of the resultant vector = \sqrt{x^{2}+y^{2}},where

x represents the horizontal vector and y represents the vertical vector

<em><u>The direction</u></em> of the resultant vector is tan^{-1}\alpha, where α

is the angle between the horizontal vector and the resultant vector

Vector 1 is 5 cm due to West-axis

Vector 2 is 3 cm due to South-axis

We need to find the resultant displacement of them

The West and South are perpendicular

The West is the horizontal vector and South is the vertical vector

The magnitude of the resultant displacement s is:

s=\sqrt{(5)^{2}+(3)^{2}}

s=\sqrt{25+9}

s=\sqrt{34}=5.8

The direction of the resultant displacement s is:

tan^{-1}\frac{3}{5}=31° south of the west (between the west and

the resultant displacement)

<em>The resultant displacement is 5.8 cm, 31° South of the West axis</em>

6 0
3 years ago
In rural areas, water is often extracted from underground by pumps. Consider an underground water source whose free surface is 6
stealth61 [152]

Answer:

W = 9533.09 Watt

Explanation:

given,

diameter of pipe inlet, d₁ = 10 cm

                                      r₁ = 5 cm

diameter of pipe outlet, d₂ = 15 cm

                                      r₂= 7.5 cm

head upto water level is to rise = 60 + 5

                                          = 65 m

flow rate = 0.015 m³/s

we know

A₁ v₁ = A₂ v₂ = Q  

 π r₁² v₁ = π r₂² v₂  = 0.015

 v_1= \dfrac{r_2^2}{r_1^2} v_2

 v_1= \dfrac{7.5^2}{5^2} v_2

 v_1= 2.25 v_2

 v_2 = \dfrac{0.015}{\pi r_2^2}

 v_2 = \dfrac{0.015}{\pi 0.075^2}

    v₂ = 0.848 m/s

    v₁ = 1.908 m/s

Applying Bernoulli's equation

 P_p = \dfrac{1}{2}\rho (v_2^2-v_1^2)+ \rho g h

 P_p= \dfrac{1}{2}\times 1000\times (0.848^2-1.908^2)+ 1000\times 9.8\times 65

 P_p= 635539.32 Pa

 P_p is the pump pressure

Power of the pump

W = P_p x Q

W = 635539.32 x 0.015

W = 9533.09 Watt

6 0
4 years ago
What a not an aspect of relative wind
daser333 [38]
Relative wind<span> is defined as the airflow relative to an airfoil.</span>
4 0
3 years ago
Read 2 more answers
What type of electromagnetic radiation can be used as a medical tracer to diagnose disease by being sent through the body's circ
Stolb23 [73]
It c.microwaves !!!!!!!!!!
4 0
3 years ago
A 0.68 kg squirrel is resting on a branch 8 meters above the ground. What is the gravitational potential energy of a squirrel? A
ANEK [815]

Answer:

The gravitational potential energy of a squirrel is 53.312 J.

Explanation:

We have,

Mass of a squirrel is 0.68 kg

It is placed at a height of 8 m above the ground.

It is required to find the gravitational potential energy of a squirrel. It is possessed by an object due to its position. Its formula is given by :

E=mgh\\\\E=0.68\times 9.8\times 8\\\\E=53.312\ J

So, the gravitational potential energy of a squirrel is 53.312 J.

7 0
3 years ago
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