What are the restrictions on the domain of g o h?
2 answers:
and h(x)= 2x-8
g o h is a composition function
First we find g o h
g o h is g(h(x))
We plug in h(x) in g(x)
We replace x with 2x-8 in g(x)
To find domain we look at the domain of h(x) first
Domain of h(x) is set of all real numbers
now we look at the domain of g(h(x))
Negative number inside the square root is imaginary. so we ignore negative number inside the square root
So to find domain we set 2x - 12 >=0 and solve for x
2x - 12 >=0
add both sides by 12
2x >= 12
divide both sides by 2
x > = 6
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Answer:
a) P(X>np+3=0.017
b) P(x>1)=0.190
c) P(Y>1)=0.651
Step-by-step explanation:
This a binomial experiment where success is denoted by parts that need rework.
X ∼ B(n, p); n = 20; p = 0.01
The expected value of X is: E(X) = np =20×0.01= 0.2
The variance is: Var(X) = np(1 − p) = 0.2 × 0.99 = 0.198,
The standard deviation SD(X)= ≈ 0.445
a) P(X>np+3=P(X>0.2+3×0.445)=P(X>1.535)=P(X≥2)
Probability function is given by:
P(X≥2)=1-P(X<2)=1-P(X=1)-P(X=0)= 1 - -
P(X≥2)=1-0.165-0.818=0.017
b) p=0.04
P(x>1)=P(x≥2)= 1 - P(x=1) - P(x=0)= 1 - -
P(x>1)= 1 - 0.368 - 0.442=0.190
c) In this case we consider p=0.19 (Probability that X exceeds 1)
In this experiment Y is the number of hours and n= 5 hours.
Then, we check the probability in each hour:
P(Y>1)=1- P(Y=0)
P(Y=0)==0.349
P(Y>1)=1-0.349=0.651