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Inga [223]
2 years ago
14

Can somebody plz help answer all these questions CORRECT thanksss!

Mathematics
1 answer:
Natali5045456 [20]2 years ago
3 0

Answer:

37%, 93%, 58%, 21%, 54%, 13%, 34%, 90%, 80%, 52%, 35%

Step-by-step explanation:

37/100 = 37%, 93/100 = 93%, 58/100 = 58%, 21/100 = 21%, 54/100 = 54%, 13/100 = 13%, 17/50 = 34/100 = 34%, 9/10 = 90/100 = 90%, 4/5 = 80/100 = 80%, 13/25 = 52/100 = 52%, 7/20 = 35/100 = 35%

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Can someone help me please
Softa [21]
The answer is 3,696 m3
3 0
3 years ago
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Ecuación de la hipérbola con centro en (0;0), focos en abrir paréntesis 0 coma espacio menos raíz cuadrada de 28 cerrar paréntes
yaroslaw [1]

Answer:

\frac{y^{2}}{25}-\frac{x^{2}}{3}=1

Step-by-step explanation:

Para resolver este problema debemos tomar en cuenta los datos que nos dan y la ecuación de una hipérbola. Comencemos con los datos:

centro: (0,0)

focos: (0,-\sqrt{28}),(0,\sqrt{28})

eje conjugado = 2\sqrt{3}

por los focos podemos ver que la hipérbola se dirige hacia el eje y, por lo que debemos tomar la siguiente forma de la ecuación de la parábola:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

de los focos podemos obtener que:

c=\sqrt{28}

y del eje conjugado podemos saber que al dividir la longitud del eje conjugado dentro de 2 obtenemos b, así que:

b=\sqrt{3}

podemos utilizar la siguiente fórmula para obtener a:

c^{2}-a^{2}=b^{2}

si despejamos a en la ecuación obtenemos lo siguiente:

a=\sqrt{c^{2}-b^{2}}

ahora podemos sustituir los valores:

a=\sqrt{(\sqrt{28})^{2}-(\sqrt{3})^{2}}

a=\sqrt{28-3}

a=\sqrt{25}

a=5

así que media vez conozcamos a, podemos sustituir los datos en la ecuación de la hipérbola así que obtenemos lo siguiente:

\frac{y^{2}}{a^{2}}+\frac{x^{2}}{b^{2}}=1

\frac{y^{2}}{(5)^{2}}+\frac{x^{2}}{(\sqrt{3})^{2}}=1

\frac{y^{2}}{25}+\frac{x^{2}}{3}=1

si graficamos la hipérbola, queda como en el documento adjunto.

7 0
2 years ago
Here it is^ algebra 1
Kamila [148]
Is (2,4) a solution for y <= 3x -1 ??
answer : No
x = 2, replace it in the equation
y <= 3(2) - 1
y<= 5
--_(2,5)
y = 4, again replace it in equation
4 <= 3x - 1
3x <= 5
x <= 5/3
--_(5/3,4)

3 0
3 years ago
Solve the equation for principal values of x. Express solutions in degrees.
Hitman42 [59]

Option C:

x = 90°

Solution:

Given equation:

\sin x=1+\cos ^{2} x

<u>To find the degree:</u>

\sin x=1+\cos ^{2} x

Subtract 1 + cos²x from both sides.

\sin x-1-\cos ^{2} x=0

Using the trigonometric identity:\cos ^{2}(x)=1-\sin ^{2}(x)

\sin x-1-\left(1-\sin ^{2}x\right)=0

\sin x-1-1+\sin ^{2}x=0

\sin x-2+\sin ^{2}x=0

\sin ^{2}x+\sin x-2=0

Let sin x = u

u^2+u-2=0

Factor the quadratic equation.

(u+2)(u-1)=0

u + 2 = 0,  u – 1 = 0

u = –2, u = 1

That is sin x = –2, sin x = 1

sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.

sin x = 1

The value of sin is 1 for 90°.

x = 90°.

Option C is the correct answer.

3 0
2 years ago
Read 2 more answers
Can someone please help me with these two questions ​
Anarel [89]

Answer:

  23.  0.4583 seconds

  24.  0.0107 seconds

Step-by-step explanation:

The problem statement tells you how to work it. You need to convert speed from miles per hour to feet (or inches) per second.

 90 mi/h = (90·5280 ft)/(3600 s) = 132 ft/s = (132·12 in)/s = 1584 in/s

__

23. The time it takes for the ball to travel 60.5 ft is ...

  time = distance/speed

  time = (60.5 ft)/(132 ft/s) = 0.4583 s

It takes 458.3 milliseconds to reach home plate.

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24. time = distance/speed

  time = (17 in)/(1584 in/s) = 0.0107 s

The ball is in the strike zone for 10.7 milliseconds.

4 0
3 years ago
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