We can set up a proportion since we know the ratio between the # of purple marbles and the # of green marbles.
A ratio is a way to compare two different values: for every 8 purple marbles there are 5 green marbles
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![\frac{8}{5} = \frac{p}{30}](https://tex.z-dn.net/?f=%5Cfrac%7B8%7D%7B5%7D%20%3D%20%5Cfrac%7Bp%7D%7B30%7D)
</h2><h2 /><h2>when we cross multiply, we get 5p = 240 </h2><h2>we divide both sides by 5 to isolate the variable </h2><h2 /><h3><u>There are 48 purple marbles </u></h3>
It should increase but I’m between stays the same or increase, I’m not sure in a 100% sorry...
For A for the mean just add them all up which would be which is 430 and divide by the number of numbers there is so 430 divided by 8 = 53.75 and the median order them from least to greatest and find the one in the middle which is 52 and 56 when there's two just add them and then divide it by 2 which is 54
Hope this helped :)
The answer is the second option