There are 2 options to solve that.
1. The first one is by derivatives.
f(x)=x^2+12x+36
f'(x)=2x+12
then you solve that for f'(x)=0
0=2x+12
x=(-6)
you have x so for (-6) solve the first equation, then you find y
y=(-6)^2+12*(-6)+36=(-72)
so the vertex is (-6, -72)
2. The second option is to solve that by equations:
for x we have:
x=(-b)/2a
for that task we have
b=12
a=1
x=(-12)/2=(-6)
you have x so put x into the main equation
y=(-6)^2+12*(-6)+36=(-72)
and we have the same solution: vertex is (-6, -72)
For next task, I will use the second option:
y=x^2-6x
x=(-b)/2a
for that task we have
b=(-6)
a=1
x=(6)/2=3
you have x so put x into the main equation
y=3^2+(-6)*3=(--9)
and we have the same solution: vertex is (3, -9)
Visualize the image in your mind and you can see that it forms a right angled triangle with a base,altitude and hypotenuse
base=2 feet
hypotenuse(ladder)=13 ft
We need to find the altitude,
By applying pythagoras theorem,
base square+altitude square=hypotenuse square
Take altitude as x
2 square+x square=13 square
4+x square=169
x square=169-4
x square=165
x= root of 165
x=12.8 feet(approx.)
8 post 4ft is the length 2ft ,yes if you dived 5 from 40 that is how many post , then you dived how many posts and that is the height then you dvide that and that is your width.
Answer: 384 feet
Step-by-step explanation:
We will simplify and solve -16t² + 160t when t is equal to 4.
-16t² + 160t
-16(4)² + 160(4)
384 feet
