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3 years ago

HELP ASAP PLEASEESE <3

Mathematics

1 answer:

liubo4ka [24]3 years ago

3 0

Answer:

?? Where IS THE PICTUREEE

Step-by-step explanation:

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Todd plans to swim 18 laps in the pool. Each lap is 50 yards. So far Todd has swam 738 yards. what percentage of the total had T

oee [108]

1 lap = 50 yards
18 laps = 50 x 18 = 900 yards

Todd has swam 738 yards
Percentage completed = 738/900 x 100 = 82%

Answer: 82%

7 0

3 years ago

Read 2 more answers

Olaolu’s monthly salary is 604.18.He pays 10%as income tax per month.What is his monthly tax to the nearest naira

Ostrovityanka [42]

Answer:

₦60

Step-by-step explanation:

The amount of tax will be found by multiplying the tax rate by the amount being taxed.

The monthly tax is the tax rate times the monthly salary:

10% × ₦604.18 = ₦60.42

Olaolu's monthly tax is about ₦60.

4 0

2 years ago

The space shuttle releases a space telescope into orbit

sergey [27]

Answer: $68 m/s^{2}$

Step-by-step explanation:

The acceleration $a$ of the satellite can be calculated by the following equation:

$V_{f}=V_{o}+at$

Where:

$V_{f}=1700 m/s$ is the final speed of the satellite

$V_{o}=0$ is the initial speed of the satellite (it was "stationary" before the release)

$t=25 s$ is the time

Isolating $a$ :

$a=\frac{V_{f}}{t}$

$a=\frac{1700 m/s}{25 s}$

Finally:

$a=68 m/s^{2}$

4 0

3 years ago

Bo, Ryan and Zach walked 1/4 miles from school to Bo’s house. They walked 4/6 miles from Bo's House to the park what is the tota

BigorU [14]

Answer: They walked 11/12 miles

Step-by-step explanation:

1/4 + 4/6

3/12 + 8/12

11/12

7 0

3 years ago

The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches. Men the same

masha68 [24]

Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

Step-by-step explanation:

Let x and y area the random variable that represents the heights of women and men.

Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.

i.e. $\mu_1 = 64$ $\sigma_1=2.7$

Since , $z=\dfrac{x-\mu}{\sigma}$

Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).

[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

$z=\dfrac{72-64}{2.7}=2.96296296\approx2.96$

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.

i.e. $\mu_2 = 69.3$ $\sigma_2=2.8$

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).

[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

$z=\dfrac{70-69.3}{2.8}=0.25$

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.

6 0

3 years ago