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Sati [7]
3 years ago
8

How would you define the distance between parallel lines in a plane?

Mathematics
1 answer:
Verdich [7]3 years ago
3 0
This article is about a mathematical relationship between lines. For other uses, see Parallel (disambiguation). "Parallel lines" redirects here. For other uses, see Parallel lines (disambiguation). Line art drawing of parallel lines and curves.

In geometry, parallel lines are lines in a plane which do not meet; that is, two lines in a plane that do not intersect or touch each other at any point are said to be parallel. By extension, a line and a plane, or two planes, in three-dimensional Euclidean space that do not share a point are said to be parallel. However, two lines in three-dimensional space which do not meet must be in a common plane to be considered parallel; otherwise they are called skew lines. Parallel planes are planes in the same three-dimensional space that never meet.

Parallel lines are the subject of Euclid's parallel postulate.[1] Parallelism is primarily a property of affine geometries and Euclidean geometry is a special instance of this type of geometry. In some other geometries, such as hyperbolic geometry, lines can have analogous properties that are referred to as parallelism.


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Answer:

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1


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3 years ago
Which size bottle of ketchup is the best deal with the lowest unit price? Prices for Different Sizes of Bottles of Ketchup Size
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Answer:

a.10 oz

Step-by-step explanation:

2.50/10=10

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3 years ago
Radio signals travel at a rate of 3 × 108 meters per second. How many seconds will it take for a radio signal to travel from a s
lys-0071 [83]

Answer:

1.1888 (8 goes on forever) seconds to travel from the satellite to Earth.

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12mph and the total trip took
spayn [35]
<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then                                                                         (s + 12) = downstream speed                                                                                  (s -12) =  upstream speed 
     Given Time = 3 hours 40 minutes = 220 minutes   = (220/60) h = (11/3) h                      Time = Distance/Speed
                  33/(s +12) + 33/(s-12) = 11/3                                                                               3{33(s-12) + 33(s +12)} = 11(s+12) (s -12)                                                          99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144)                                                   99(2 s) = 11(s^{2} -144)                                                                                        198 s/11 = (s^{2} -144)                                                                                         18 s = (s^{2} -144)                                                                                            (s^{2} - 18 s - 144) = 0                                                                                         s^{2} - 24 s + 6 s -144 =0                                                                                       s(s- 24) + 6(s -24) =0                                                                                            (s -24) (s + 6) = 0                                                                                                  s -24 = 0, s + 6 =0                                                                                                s = 24, s = -6                                                                     Answer) s = 24 mph is the average speed of the boat relative to the water.  
7 0
3 years ago
WILL GIVE BRAINLIEST, THANKS, AND 5 STARS!<br> PLEASE HELP ME!
Bogdan [553]

Answer:

-4 and 4

Step-by-step explanation:

<u>Method 1</u>

Apply Difference of Two Squares Formula: a^2-b^2=(a+b)(a-b)

Given  x^2-16=0

Rewrite 16 as 4²

Therefore, a^2=x^2 and b^2=4^2

\implies a = \sqrt{x^2}=x

\implies b=\sqrt{4^2} =4

\implies x^2-16^2=(x+4)(x-4)

\implies (x+4)(x-4)=0

\implies (x+4)=0 \implies x=-4

\implies (x-4)=0 \implies x=4

<u>Method 2</u>

Given equation:

x^2-16=0

Add 16 to both sides:

\implies x^2-16+16=0 + 16

\implies x^2=16

Square root both sides:

\implies \sqrt{x^2}=\sqrt{16}

\implies x=\pm4

Therefore, x = -4, x = 4

6 0
2 years ago
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