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Sati [7]
3 years ago
8

How would you define the distance between parallel lines in a plane?

Mathematics
1 answer:
Verdich [7]3 years ago
3 0
This article is about a mathematical relationship between lines. For other uses, see Parallel (disambiguation). "Parallel lines" redirects here. For other uses, see Parallel lines (disambiguation). Line art drawing of parallel lines and curves.

In geometry, parallel lines are lines in a plane which do not meet; that is, two lines in a plane that do not intersect or touch each other at any point are said to be parallel. By extension, a line and a plane, or two planes, in three-dimensional Euclidean space that do not share a point are said to be parallel. However, two lines in three-dimensional space which do not meet must be in a common plane to be considered parallel; otherwise they are called skew lines. Parallel planes are planes in the same three-dimensional space that never meet.

Parallel lines are the subject of Euclid's parallel postulate.[1] Parallelism is primarily a property of affine geometries and Euclidean geometry is a special instance of this type of geometry. In some other geometries, such as hyperbolic geometry, lines can have analogous properties that are referred to as parallelism.


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HELP ME PLEASE!!! I’ll give points
Fiesta28 [93]

Answer:

85 degrees

Step-by-step explanation:

5 and 7 are equal and 7 and 11 are also equal so 5 and 11 are equal to each other

3 0
3 years ago
12 bars of soap for $8.69
Deffense [45]
Wow… how is this a question? .-.
8 0
3 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
Factor-
Nastasia [14]

Hello from MrBillDoesMath!

Answer:

See Discussion section below

Discussion:

2x^2 + 5x + 3  = (2x+3)(x+1) which is Choice 3


3x^2+10x+4  =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)

I don't think any of the provided choices are right!


8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2


6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)

I don't think any of the provided choices are right!


2x^2+x-28  =  (2x-7)(x+4) which is Choice 2


Thank you,

MrB

4 0
3 years ago
If f (x)= x-3 and g (x)= 2x-4, find (f+g)(x)
const2013 [10]

(f∘g)(x) is equivalent to f(g(x)). We solve this problem just as we solve f(x). But since it asks us to find out f(g(x)), in f(x), each time we encounter x, we replace it with g(x).

In the above problem, f(x)=x+3.

Therefore, f(g(x))=g(x)+3.

⇒(f∘g)(x)=2x−7+3

⇒(f∘g)(x)=2x−4

Basically, write the g(x) equation where you see the x in the f(x) equation.

f∘g(x)=(g(x))+3 Replace g(x) with the equation

f∘g(x)=(2x−7)+3

f∘g(x)=2x−7+3 we just took away the parentheses

f∘g(x)=2x−4 Because the −7+3=4

This is it

g∘f(x) would be the other way around

g∘f(x)=2(x+3)−7

now you have to multiply what is inside parentheses by 2 because thats whats directly in front of them.

g∘f(x)=2x+6−7

Next, +6−7=−1

g∘f(x)=2x−1

Its a lts easier than you think!

Hope this helped

5 0
3 years ago
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