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Sauron [17]
3 years ago
10

An element's identity can be determined from its

Chemistry
1 answer:
tatuchka [14]3 years ago
5 0
More than one possible answer: Atomic number, molar mass, number of protons, number of electrons (I'm talking about neutral atoms not ions).
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Which of these is the Bronsted-Lowry acid in this equation?<br> CH3- + H2O --&gt; CH4 + OH-
Juliette [100K]
H2O is the Bronsted-Lowry acid in the forward reaction, donating an H+ to CH3, and CH4 is the Bronsted-Lowry acid in the reverse direction, donating an H+ to OH-.
6 0
3 years ago
Read 2 more answers
Help help help help help
givi [52]

Answer:

D. Up-Down

Explanation:

Hoped this helped you <\3

6 0
4 years ago
Calculate ΔS° for the reaction: 4Cr(s) + 3O2(g) → 2Cr2O3(s), Substance: Cr(s) O2(g) Cr2O3(s), S°(J/K⋅mol): 23.77 205.138 81.2
Mariana [72]

<u>Answer:</u> The value of \Delta S^o for the reaction is 1051.93 J/K

<u>Explanation:</u>

Entropy change is defined as the difference in entropy of all the product and the reactants each multiplied with their respective number of moles.

The equation used to calculate entropy change is of a reaction is:

\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]

For the given chemical reaction:

4Cr(s)+3O_2(g)\rightarrow 2Cr_2O_3(s)

The equation for the entropy change of the above reaction is:

\Delta S^o_{rxn}=[(2\times \Delta S^o_{(Cr_2O_3(s))})]-[(4\times \Delta S^o_{(Cr(s))})+(3\times \Delta S^o_{(O_2(g))})]

We are given:

\Delta S^o_{(Cr_2O_3(s))}=881.2J/K.mol\\\Delta S^o_{(O_2(g))}=205.13J/K.mol\\\Delta S^o_{(Cr(s))}=23.77J/K.mol

Putting values in above equation, we get:

\Delta S^o_{rxn}=[(2\times (881.2))]-[(4\times (23.77))+(3\times (205.13))]\\\\\Delta S^o_{rxn}=1051.93J/K

Hence, the value of \Delta S^o for the reaction is 1051.93 J/K

5 0
4 years ago
Which of the following changes to a system WILL NOT result in an increase in the system’s pressure?
Sophie [7]

Answer:

B. All the rest raise P.

Explanation:

6 0
3 years ago
The iupac name for ch3–ch2–c ≡ c–ch3 is ________
NNADVOKAT [17]
The IUPAC name of the compound <span>ch3–ch2–c ≡ c–ch3 is PEN-2-YNE or 2-PENTYNE.

Attached below is a diagram that fully explains how the name was given and derived.</span>

7 0
4 years ago
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