Answer:
2Fe(s) + 3Cl2(g) → 2FeCl3(s)
Explanation:
Step 1: Data given
iron = Fe = solid = Fe(s)
chlorine = Cl2 = gas = Cl2(g)
iron(III) chloride = FeCl3 = solid = FeCl3(s)
Step 2: The unbalanced equation
Fe(s) + Cl2(g) → FeCl3(s)
Step 3: Balancing the equation
Fe(s) + Cl2(g) → FeCl3(s)
On the left we have 2x Cl (in Cl2) and on the right side we have 3x Cl (in FeCl3). To balance the amount of Cl we have to multiply Cl2 (on the left) by 3 and FeCl3 by 2.
Fe(s) + 3Cl2(g) → 2FeCl3(s)
On the left side we have 1x Fe and on the right side we have 2x Fe (in 2FeCl3). To balance the amount of Fe, we have to multiply Fe on the left side by 2. Now the equation is balanced.
2Fe(s) + 3Cl2(g) → 2FeCl3(s)
Answer:
Standardisation is used to determine the concentration of a volumetric solution in order to achieve accurate and reliable titration results
Answer:
The molarity of the diluted solution is 1.786 M
Explanation:
Dilution is a process in which you always start with a concentrated solution to which a greater volume of solvent is added. This modifies the concentration and volume of the resulting solution, but the amount of solute used to prepare the initial solution remains the same.
In summary, in a dilution the amount of solute does not vary, but the volume of the solvent varies: when more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.
The following rule is fulfilled:
Vinicial x Cinicial = Vfinal x Cfinal
where:
- Vinicial = Initial volume.
- Cinicial = Initial concentration
- Vfinal = Final volume
- Cfinal = Final concentration
In this case:
- Vinicial= 250 mL= 0.25 L (Being 1 L=1000 mL)
- Cinicial= 12.5 M
- Vfinal= 1.5 L+ 0.25 L=1.75 L
- Cfinal= ?
Replacing:
0.25 L* 12.5 M= 1.75 L* Cfinal
Solving:

Cfinal= 1.786 M
<u><em>The molarity of the diluted solution is 1.786 M</em></u>
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