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Solnce55 [7]
3 years ago
14

You are asked to write an app to keep track of a relatively small music library. The app should load song information from a dat

a file once the app is started. It should allow user to view, add, remove, and search for songs. The app should save the data back to the same data file when the program exits.
Computers and Technology
1 answer:
gogolik [260]3 years ago
6 0

Answer:

C++ PROGRAM

Explanation:

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Write a function called median, that takes as parameter a full, sorted array of doubles and returns the median of the list. For
trapecia [35]

Answer:

Explanation:

public class Lab8

{

public static double median(double list[])

{

int size=list.length;

if(size%2!=0)

return list[size/2];

else

return(list[size/2-1]+list[size/2])/2.0;

}

public static boolean issorted(double list[])

{

for(int i=0;i<list.length-1;i++)

{

if(list[i]>list[i+1])

return false;

}

return true;

}

public static void findcommon(int a1[],int a2[],int common[])

{

int c=0;

for(int i=0;i<a1.length;i++)

{

boolean isFilled=false;

for(int j=0;j<c;j++)

{

if(a1[i]==common[j])

{

isFilled=true;

break;

}

}

if(isFilled)

{

for(int k=0;k<a2.length;k++)

{

if(a1[i]==a2[i])

{

common[c]=a1[i];

c++;

break;

}

}

}

}

while(c<common.length)

{

common[c]=0;

c++;

}

}

public static void rotateRight(int list[])

{

int temp=list[list.length-1];

for(int i=list.length-1;i>0;i--)

{

list[i]=list[i-1];

}

list[0]=temp;

}

public static int count(int list[],int n)

{

int ncount=0;

for(int i=0;i<list.length;i++)

{

if(list[i]==n)

ncount++;

}

return ncount;

}

public static int[] stretch(int list[])

{

int stretchedList[]=new int[list.length*2];

int k=0;

for(int i=0;i<list.length;i++)

{

int n=list[i];

if(n%2==0)

{

stretchedList[k]=n/2+1;

stretchedList[k+1]=n/2;

}

k+=2;

}

return stretchedList;

}

public static void printDoubleArray(double arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void printIntArray(int arr[])

{

System.out.print("[");

for(int i=0;i<arr.length;i++)

{

if(i!=arr.length-1)

System.out.print(arr[i]+",");

else

System.out.print(arr[i]);

}

System.out.println("]");

}

public static void main(String[] args)

{

double list1[]={1.1,2.2,3.3,4.4,5.5,6.6};

double med=median(list1);

System.out.println("List1:");

printDoubleArray(list1);

System.out.println("Median of List1:"+ med);

double list2[]={1.1,2.2,3.3,4.4,6.6,5.5};

boolean result=issorted(list2);

System.out.println("List2:");

printDoubleArray(list2);

System.out.println("List2 is a sorted array.(T/F):"+ result);

int list3[]={3,8,5,6,5,8,9,2};

int list4[]={5,15,4,6,7,3,9,11,9,3,12,13,14,9,5,3,13};

int list5[]=null;

if(list3.length<=list4.length)

list5=new int[list3.length];

else

list5=new int[list4.length];

findcommon(list3,list4,list5);

System.out.println("\n List3:");

printIntArray(list3);

System.out.println("\n List4:");

printIntArray(list4);

System.out.println("\n Array with common value,List5:");

printIntArray(list5);

int list6[]={3,8,19,7};

System.out.println("\n List6:");

printIntArray(list6);

rotateRight(list6);

System.out.println("\n the array after rotate right:");

printIntArray(list6);

int list7[]={3,5,2,1,92,38,3,14,5,73};

int n=count(list7,3);

System.out.println("\n List7:");

printIntArray(list7);

System.out.println("\n the number of occurences of the value 3 in the list 7:"+ n);

int list8[]={18,7,4,24,11};

int list9[]=stretch(list8);

printIntArray(list8);

System.out.println("\n The array after stretching:");

printIntArray(list9);

}

}

8 0
3 years ago
Why aren't the answers visible anymore? Thanks!
olga55 [171]

Answer:

i am wondering the same thing please help

Explanation:

7 0
4 years ago
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Using truth table, prove that:<br><br> (A + B). C = (A . C)+ (B .C) ?
Genrish500 [490]

Answer:

The image of truth table is attached.

Explanation:

In the truth table there is a separate table for the expression (A+B).C and for the expression (A.C)+(B.C) you can see in the truth table that the columns of (A+B).C is having same values as the (A.C)+(B.C).Hence we can conclude that (A+B).C is equal to (A.C)+(B.C).

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3 years ago
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Answer:

try closing the tab or app and logging back in

Explanation:

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In memory ads for DIMMs, you notice DDR 2400 CL15 in one ad and PC4 21300 CL9 in another. Which ad is advertising the faster mem
Artyom0805 [142]

Answer:

The answer is 'PC4 21300 CL9".

Explanation:

Faster memory advertising is used to provide customer memory, which is essential for brand actions. It can't be taken throughout ad coverage. Retired-laboratory tests revealed its access to ad-memory detection aspects of the effect of its grade through publicity recovery, that's why it uses the PC4 21300 CL9, it transfers the 170400 bits per second.

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